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Kitty [74]
3 years ago
10

The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

Width = 18 inches

Length = 59 inches

Step-by-step explanation:

The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions

Perimeter of a rectangle = 2L + 2W

The length of a rectangle is five more than triple the width.

L = Length = 5 + 3W

W = Width

If the perimeter is 154 inches, what are the dimensions

Hence,

154 = 2L + 2W

154 = 2(5 + 3W ) + 2W

154 = 10 + 6W + 2W

Collect like terms

154 - 10 = 8W

144 = 8W

W = 144/8

W = 18 inches

Length = 5 + 3W

Length = 5 + 3(18)

Length = 5 + 54

Length = 59 inches

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The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

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Question 6
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3 years ago
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jarptica [38.1K]

Answer:

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The tength of a picture frame is 12 cm more than twice the width. If the perimeter is 204cm, find the
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Answer:

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Step-by-step explanation:

The perimeter is the measurements of all sides added together. Let's start by dividing the perimeter by 2, so we have the sum of the length and width. This gives us 102cm. Let's call the width <em>x</em>, and the length <em>y</em>. We know <em>y</em> is <em>x</em> times 2 plus 12. (2x + 12) So, we know [x + y = x + (2x + 12)]. So let's solve.

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