On what interval is the function positive?

Mathematics

1 answer:

Lesechka [4]3 years ago

4 0

Answer: (-∞,2)

Step-by-step explanation: 2 is not included in the interval since at x=2, the function crosses the x axis, meaning it is not positive, and instead 0.

All x values below 2 are positive.

You might be interested in

Three roots of a fifth degree polynomial function f(x) are -2, 2, and 4 + i. Which statement describes the number and nature of

Juli2301 [7.4K]

We know that imaginary roots always come in pairs, so we already know 4 solutions

-2, 2, 4 + i and a pair of 4 + i

Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots

So for sure, we will have 3 real roots and 2 imaginary roots

Last option, f(x) has three real roots and two imaginary roots

3 0

3 years ago

Need help plzzzz!!!!

uysha [10]

Answer:

11a. 15x + 6

11b. x + 8 < 16 or x + 8 - 16

12. 3x + 15 + 5x = 8x + 15

13. 7x + 31

Step-by-step explanation:

5 0

2 years ago

What is the answer for part b

trasher [3.6K]

Answer:

(-3,-10)

Step-by-step explanation:

Given part a, you seem to know the midpoint formula. We can easily edit that to figure out what an endpoint is. Say that a variable "a" represents the x coordinate of D, and b the y coordinate. As the x coordinate of M is 0.5, and the x coordinate of C is 2, we can use the midpoint formula to say that $\frac{a+2}{2} =-0.5$ . Multiplying both side by 2, we get that a+2=-1, and subtracting both sides by 2, a=-3. Similarly, $\frac{b+7}{2} =-1.5$ , b+7=-3, and b=-10, making our answer (-3, -10). Let me know if you have any questions.