On what interval is the function positive?

Mathematics

1 answer:

Lesechka [4]2 years ago

4 0

Answer: (-∞,2)

Step-by-step explanation: 2 is not included in the interval since at x=2, the function crosses the x axis, meaning it is not positive, and instead 0.

All x values below 2 are positive.

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Please help me<br><br> Determine the value of base b if (152)b = 0x6A. Please show all steps.

egoroff_w [7]

Answer:

The value of b is, 8

Step-by-step explanation:

To determine the value of b:

Given:

$(152)_b = 0x6A$ ....[1]

Since, 0x6A represents the hexadecimal form.

To convert this hexadecimal form into decimal form:

$(6A)_{16}= (6 \times 16^1)+(A \times 16^0)=(6 \times 16)+(10 \times 1) =96+10 = 106$

⇒ $0x6A=106$ (decimal form)

Now we have to convert this decimal form into octal

8 | 106

8 | 13 | 2

| 1 | 5

Then, the octal form we get, $(152)_8$

Substitute this in [1] we have;

$(152)_b = (152)_8$

On comparing both sides we have;

b = 8

Therefore, the value of b is, 8

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3 years ago

Which equation is the direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3

Otrada [13]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{f(x)}{y}=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=-18\\
x=3
\end{cases}\implies -18=k3
\\\\\\
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