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3 years ago

Evaluate the piecewise function at the indicated values from the domain:

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

In this question, we given a piece-wise function, that has different definitions depending on the domain.

Evaluate the function at x = 0.

The exercise asks for us to evaluate the function at $x = 0$

We have to look at the definition, and see which definition includes $x = 0$ . The equal sign at $x = 0$ is on the second definition, that is:

$f(x) = 1, 0 \leq x < 2$

Thus, at $x = 0$ , the value of the function is 1, and the correct answer is given by option A.

For another example of evaluation of a piece-wise function, you can check brainly.com/question/17966003

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SU and VT are chords that intersect at point R.

vovikov84 [41]

Answer:

<h2>The length of the line segment VT is 13 units.</h2>

Step-by-step explanation:

We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

$\frac{RS}{RT} =\frac{RV}{RU}$

Where

$RS=SR=x+6\\RT=x+4\\VR=RV=x+1\\RU=x$

Replacing all these expressions, we have

$\frac{x+6}{x+4} =\frac{x+1}{x}$

Solving for $x$ , we have

$x(x+6)=(x+4)(x+1)\\x^{2} +6x=x^{2} +x+4x+4\\6x-5x=4\\x=4$

Now, notice that chord VT is form by the sum of RT and RV, so

$VT=VR+RT\\VT=x+1+x+4\\VT=2x+5$

Replacing the value of the variable

$VT=2(4)+5\\VT=8+5\\VT=13$

Therefore, the length of the line segment VT is 13 units.

5 0

3 years ago

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What’s 2 x 21 whats the answer

swat32

Answer:

Step-by-step explanation:

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3 years ago

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Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$