Answer
C) 160 in^2
Step by step explanation
First, let's find the area of the rectangle.
Area of a rectangle = length x width
The area of the rectangle = 20 * 10
= 200 in^2
Now let's find the area of the triangle that is removed.
Area of a triangle = 1/2 base * height.
Here base = 10 and height = 8. Plug in these values into the formula, we get
Area of the triangle = 1/2 * 10*8
= 5* 8
The area of the triangle = 40 in^2
The area of the remaining figure = Area of the rectangle - area of the triangle
= 200 - 40
= 160 in^2
The answer is "160 in^2"
Thank you.
Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths 
is
So the solution here is
Answer:
2²
Step-by-step explanation:
The prime factorization is only prime numbers multiplied
4 is 2(2) which is
2²
Answer:
angle C = 78
angle D = 108
Step-by-step explanation:
the measure of angle A is 102
To find the measure of angle C
let Angle C be x
102 + x = 180 (linear pair)
x = 180 -102
x = 78
angle C = 78
angle B = 78 (vertically opposite angles are equal)
angle D = 108 (vertically opposite angles are equal)
