Answer:
The number of adult admissions was 12 and the the number of child admissions was 17
Step-by-step explanation:
Let
a ----> represent the number of adult admissions
c ----> represent the number of child admissions
we know that
A group of 29 people attending the zoo paid a total of $222 in admission fees
so
![a+c=29](https://tex.z-dn.net/?f=a%2Bc%3D29)
----> equation A
----> equation B
Solve using the substitution method
substitute equation A in equation B
![10(29-c)+6c=222](https://tex.z-dn.net/?f=10%2829-c%29%2B6c%3D222)
solve for c
![290-10c+6c=222\\4c=68\\c=17](https://tex.z-dn.net/?f=290-10c%2B6c%3D222%5C%5C4c%3D68%5C%5Cc%3D17)
Find the value of a
![a=29-17=12](https://tex.z-dn.net/?f=a%3D29-17%3D12)
therefore
The number of adult admissions was 12 and the the number of child admissions was 17
Midpoint = ( (x1+x2)/2, (y1+y²)/2 )
so ( 6+25 /2, 8+20 /2 )
or (31/2, 14)
Answer:
3/5 you’ll need to divide that section into 5- 3/5th are shaded
6/10 divide that section into 10 6/10 are shaded
Step-by-step explanation:
Answer:
No i do for other stuff but not this and the answer is 18
Step-by-step explanation: