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valina [46]
3 years ago
10

A regular octagon has an apothem measuring 10 in. and a perimeter of 66.3 in. What is the area of the octagon, rounded to the ne

arest square inch? 88 in.2 175 in.2 332 in.2 700 in.2
Mathematics
2 answers:
kupik [55]3 years ago
8 0
<h2>Hello!</h2>

The answer is: 332in^{2}

<h2>Why?</h2>

From the statement we know that the octagon has a apothem of 10in and a perimeter of 66.3in, and we are asked to find the area of the octagon.

We can use the following formula:

A=\frac{Perimeter*Apothem}{2}

Substituting the given information into the area formula, we have:

A=\frac{66.3in*10in}{2}\\\\A=\frac{663in}{2}=331.5in^{2}

Rounding to the nearest number we have that:

331.5 ≈ 332

So, the area of the octagon is: 332in^{2}

Have a nice day!

Lerok [7]3 years ago
4 0

Answer:

332in^2

Step-by-step explanation:

The area of a regular polygon is calculated using the formula;

Area=\frac{1}{2}ap

where a is the apothem and p is the perimeter.

It was given that, the apothem is, a=10in. and the perimeter is p=66.3 in.

We substitute into the formula to obtain;

Area=\frac{1}{2}\times10\times66.3in^2

Area=331.5in^2

To the nearest square inch, we have;

Area=332in^2

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