Solve for y.

Suppose that 35 people are divided in a random mannerinto two teams in such a way that one team contains10 people and the other

Alisiya [41]

To be precise, the size of your sample space is (2410)(2410). This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, (22)(22) (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are 24−2=2224−2=22 nondefective bulbs, and I must choose 88 of them, so that's (228)(228). Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: (22)(228)(22)(228)

P=(22)(228)(2410)P=(22)(228)(2410)

Or, since (22)=1(22)=1,

P=(228)(2410)P=(228)(2410)

Hope this helps!

7 0

2 years ago

What is the proportional relationship represented by this table?

77julia77 [94]

Answer:

the constant of proportionality is 0.2 and it is a proportional relationship

Step-by-step explanation:

2 divided by 10 is 0.2

1 divided by 5 is 0.2

they have the same answer so they are proportional

since they have the answer 0.2 it

is there constant of proportionality

4 0

3 years ago

How do you find the equation of a triangles altitude using point slope formula?

forsale [732]

1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. 
(Scroll Down for Answer!)Answer by jim_thompson5910(34047) (Show Source):You can put this solution on YOUR website!
If we plot the points and connect them, we get this triangle:

Let point
A=(xA,yA)
B=(xB,yB)
C=(xC,yC)

-------------------------------
Let's find the equation of the segment AB

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through AB is

-------------------------------
Let's find the equation of the segment BC

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through BC is

-------------------------------
Let's find the equation of the segment CA

Start with the general formula

Plug in the given points

Simplify and combine like terms

So the equation of the line through CA is

So we have these equations of the lines that make up the triangle

So to find the equation of the line that is perpendicular to that goes through the point C(2,-5), simply negate and invert the slope to get

Now plug the slope and the point (2,-5) into

Solve for y and simplify

So the altitude for vertex C is

Now to find the equation of the line that is perpendicular to that goes through the point A(4,5), simply negate and invert the slope to get

Now plug the slope and the point (2,-5) into

Solve for y and simplify

So the altitude for vertex A is

Now to find the equation of the line that is perpendicular to that goes through the point B(-4,1), simply negate and invert the slope to get

Now plug the slope and the point (-4,1) into

Solve for y and simplify

So the altitude for vertex B is

------------------------------------------------------------
Now let's solve the system

Plug in into the first equation

Add 2x to both sides and subtract 2 from both sides

Divide both sides by 3 to isolate x

Now plug this into

So the orthocenter is (-2/3,1/3)

So if we plug in into the third equation , we get

So the orthocenter lies on the third altitude

3 0

3 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

So

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

7 0

3 years ago

When Jose took the test over, he increased his score by 15 percentage points. Jose raised his score to an 83% on the test. Which

JulsSmile [24]

Increased by 15
past score was x
increased by 15 means he raised to 15+x
it was raised to 83%

therefor
x+15=83

first option is right (and first test was 68%)

5 0

3 years ago

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