The frequency table, stem and leaf plot, and histogram are attached.
The histogram looks similar to the stem and leaf plot, except turned on its side. It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.
The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table. Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.
Okay so first u just add the terms on each side
2t-18>-6-100t
2(t-9)>2(-3-50t)
t-9>-3-50t
51t>6
t>6/51
t>2/17
so just take a number line put an empty circle like this : O on 2/17 and draw a line showing it continues to the right infinitely. Sorry if my math is wrong lol i am functioning on one hour of sleep.
Answer:
4th option, 5 5/6
Step-by-step explanation:
8 1/2 - 2 2/3
= 17/2 - 8/3
= (51-16)/6
= 35/6
= 5 5/6
Answered by GAUTHMATH
Answer:
Step-by-step explanation:
Let X be the length of pregnancy.
X is N(268, 15)
a) Prob of pregnancy lasting 307 days or longer
= P(X>307) = 
=0.5-0.4953
=0.0047
b) Lowest 2% is 2nd percentile
Z=-2.55
X score = 268-2.55(15)
= 229.75 days
If length of days >230 days then it is not premature.