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Alenkinab [10]
3 years ago
13

John runs a computer software store. Yesterday he counted 135 people who walked by the store, 58 of whom came into the store. Of

the 58, only 21 bought something in the store. (Round your answers to two decimal places.)
Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

my name is Thor the answer is false mark me in arsenal

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The list shows the number of songs on each album Dakota has downloaded.
PtichkaEL [24]
The frequency table, stem and leaf plot, and histogram are attached.

The histogram looks similar to the stem and leaf plot, except turned on its side.  It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.

The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table.  Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.

3 0
3 years ago
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Solve and graph <br> -4 + 2t - 14 - 18t &gt; -6 - 100t
irina [24]
Okay so first u just add the terms on each side 
2t-18>-6-100t  
2(t-9)>2(-3-50t)
t-9>-3-50t
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t>6/51
t>2/17
so just take a number line put an empty circle like this : O on 2/17 and draw a line showing it continues to the right infinitely. Sorry if my math is wrong lol i am functioning on one hour of sleep. 
7 0
3 years ago
Free brainliest whoever can guess my character name??
Sunny_sXe [5.5K]
Marinette Dupain-Cheng
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3 years ago
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Need help ASAP with this question please
Assoli18 [71]

Answer:

4th option, 5 5/6

Step-by-step explanation:

8 1/2 - 2 2/3

= 17/2 - 8/3

= (51-16)/6

= 35/6

= 5 5/6

Answered by GAUTHMATH

6 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the pro
Bogdan [553]

Answer:

Step-by-step explanation:

Let X be the length of pregnancy.

X is N(268, 15)

a) Prob of pregnancy lasting 307 days or longer

= P(X>307) = P(Z>\frac{307-268}{15} )\\=P(Z>2.6)\\

=0.5-0.4953

=0.0047

b) Lowest 2% is 2nd percentile

Z=-2.55

X score = 268-2.55(15)

= 229.75 days

If length of days >230 days then it is not premature.

4 0
3 years ago
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