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3 years ago

An item costs $440 before tax, and the sales tax is $13.20.

Mathematics

1 answer:

Ahat [919]3 years ago

3 0

Answer:

Step-by-step explanation:

13.2 / 440 = 0.03

0.3*100 = 3%

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Words problems involving length and money

stiv31 [10]

Answer:

Step-by-step explanation:

Since 8 poster takes 48 inches of tape

48/8 = 6

each poster will take 6

if you have two posters

6x2=12

so 12

5 0

2 years ago

Read 2 more answers

Use the distributive property to write the expression without parentheses 6(7a+6)

alexandr1967 [171]

Answer:

42a+36

Step-by-step explanation:

6(7a+6)

Distribute

6*7a + 6*6

42a+36

3 0

3 years ago

Read 2 more answers

Translate each question.<br> Four times the difference of a number and 7 is 32

schepotkina [342]

“Four times the difference of a number and 7 is 32”
Translation-
4(x-7)=32

6 0

3 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.

$y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7$

Substitute these into the ODE to see everything checks out:

$2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14$

5 0

3 years ago

Tan 1.1 – tan 4.6/

VladimirAG [237]

The value of the given equation is –0.37458.

Solution:

Given equation is:

$$\frac{\tan 1.1-\tan 4.6}{1+\tan 1.1 \tan 4.6}$

Let us first find the values.

The value of tan 1.1 = 1.96475

The value of tan 4.6 = 8.86017

Substitute these values in the given equation.

$$\frac{\tan 1.1-\tan 4.6}{1+\tan 1.1 \tan 4.6}$

$$=\frac{1.96475-8.86017}{1+1.96475 \times 8.86017}$

$$=\frac{-6.89542}{1+17.4080}$

$$=\frac{-6.89542}{18.4080}$

= –0.37458

$$\frac{\tan 1.1-\tan 4.6}{1+\tan 1.1 \tan 4.6}=-0.37458$

Hence the value of the given equation is –0.37458.

7 0

3 years ago