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Liula [17]
3 years ago
11

Help me out answer both and show work please, tysvm!!

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0
I couldn’t answer the first one sorry

Answer ($3.30 or three dollars and thirty cents)

I’ve never been taught this before but I hope I helped and got it right! (Sorry if I got it wrong) So what it says is the artist has 2 liters of paint for a project. So in 1 liter, there’s 1000 milliliters. So in 2 liters there’s 2000 milliliters in all. It says he ended off with 350 milliliters left, and each milliliter costs 2 cents. So what I did was, I subtracted 350 by 2000 (which is the milliliters) and got 1650. Next what I did was multiplied 0.2 to 1650, (the 0.2 is the cents) and got 330. Next what I did was 1650 divided 330 and got 5. Next what I did to try and check if I was correct was 5 times 330 and I got 1650. (I’ve never done this but I tried my best so sorry if I got it wrong but if I got it right you are welcome).

(Also the answer is 3.30 or three dollars and thirty cents)
andrew-mc [135]3 years ago
4 0

Answer:

1.4 liter is 1400 ml

then we will divide 7 from 1400

1400/7 = 200

200 ml of the water drip out.

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Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

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Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

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minus 4 both sideds
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(x,y)
(2,0)
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3 years ago
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