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3 years ago

Which statement about the graph of the line y=x+1/2 will be true if the 1/2 is replaced by -2

Mathematics

1 answer:

Semmy [17]3 years ago

6 0

The y-intercept (where the line hits the y-axis) will move from (0, 1/2) to (0, -2)

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Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

27÷624 as partial quotient

g100num [7]

Answer:

0.04326

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write 2.18 as a mixed number in simplest form

bezimeni [28]

It would be: 2 18/100 = 2 9/50

So, your final answer is 2 9/50

Hope this helps!

8 0

3 years ago

a jeweler buys a ring from jewelry maker for $125. he marks up the price by 135% for sale in his store. what is the selling pric

yan [13]

You wouls do 125 times 135% and that would be 168.75 then you would do 125 add 168.75 which would equal 293.75 then you would do 293.75 times 7.5% which equals 22.03 then you would do 22.03 add 293.75 and the answer would be 315.78

6 0

3 years ago

Read 2 more answers

ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -

TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0

3 years ago