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STALIN [3.7K]
3 years ago
9

How do write 412.638 using expanded form using decimals

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
400.000+10.000+2.000+0.0+0.6+0.30+0.08
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What is the coordinates for the given equation: y-2=-1/2 (x+6)
Readme [11.4K]
Slope =1.000/2.000=0.5 X-intercept=10/-1=-10.0 Y-intercept=10/2=5
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3 years ago
A student can buy notebooks for .40 each and pens for .25 each Ben needs to have at least 8 notebooks he has a total of $5 to sp
galben [10]

Answer:

He would spend at least $3.20 for the notebooks. I'm not sure what the rest of the question is, if it is long, but that should at least help!~

Step-by-step explanation:


4 0
3 years ago
Determine the value of y in the following kite.<br> (11x + 2)<br> (8y - 4)<br> (4y)<br> 134
Maru [420]
Hope this helps. Tell me if you can't read my handwriting.

6 0
3 years ago
From 1997 - 2001 the number n (in millions) of black-and-white TV S sold in the U.S. Can be modeled by n = 26.8 * (0.85) ^ t whe
Alexandra [31]

Question

a) What is the decay factor?

b) What is the percent decrease?

c) Estimate the number of black and white TV's  sold in 1999.

Answer:

a. Decay factor = 0.85

b. Percent decrease = 15%

c. 19.363  million TVs were sold

Step-by-step explanation:

Given

n = 26.8(0.85)^t

Solving (a): The decay factor

An exponential function has the form

y = ab^x

Where b is:

b = decay\ factor\ or\ growth\ factor

By comparison:

b = 0.85

Solving (b): Percentage decrease:

Percentage decrease P is calculated as follows:

P = 1 - b

Substitute 0.85 for b

P = 1 - 0.85

P = 0.15

Convert to percentage

P = 0.15*100\%

P = 15\%

Solving (c): TVs sold in 1999

First, we need to determine the value of t for 1999

In 1997, t= 0

In 1998, t= 1

In 1999, t= 2

So, we substitute 2 for t in: n = 26.8(0.85)^t

n = 26.8(0.85)^2

n = 26.8*0.7225

n = 19.363

4 0
3 years ago
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
3 years ago
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