Answer:
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Step-by-step explanation:
we know, ∠BGA = 90
In right angled triangle BGA
AB = 12 cm (diameter of circle)
⇒ (AB)2 = (AG)2 + (BG)2
⇒ 122 = 82 + (BG)2
⇒ BG = 4√5
In right angled triangle BCG
Let CG be x cm.
⇒ (BC)2 = (CG)2 + (BG)2
⇒ (BC)2 = x2 + (4√5)2 ----(1)
As we know,
⇒ (BC)2 = CG × CA ----(2)
From equation (1) and equation (2)
⇒ x2 + (4√5)2 = x × (x + 8)
⇒ x2 + (4√5)2 = x2 + 8x
⇒ 8x = 80
⇒ x = 10 cm
From equation (2)
⇒ (BC)2 = CG × CA
⇒ (BC)2 = 10 × 18 = 180
⇒ BC = √180 = 6√5
6 × 5 = 30
Answer: 3 x 7
Explanation:
So the question is asking you to multiply two prime numbers in order to get 21.
Since 3 and 7 are both prime numbers, you can express 21 as 3 x 7
Hope this helps! :)
Here is a list of prime numbers if it helps you. (prime numbers are in blue):
Public class GeometricSequence{ private double initialValue; private double multiplier; } initialValue = initial; multiplier = mult;
Answer:
x=4, y=0. (4, 0).
Step-by-step explanation:
x+3y=4
2x-6y=8
------------
x=4-3y
2(4-3y)-6y=8
8-6y-6y=8
8-12y=8
12y=8-8
12y=0
y=0/12
y=0
x+3(0)=4
x+0=4
x=4-0
x=4
It’s B because a discount takes money off a item