Look at screenshot 11 points and brainleist!

There are approximately 3.5 million deaths per year in a country express this quantity as deaths per minute

astra-53 [7]

Hmmm ok... 3.5 million.. or 3,500,000

now, keeping in mind that, there are 365 days in a year(exempting leap-year), and 24 hrs in a day, and 60 minutes in 1hr.

$\bf \cfrac{3500000~deaths}{\underline{year}}\cdot \cfrac{\underline{year}}{365~\underline{day}}\cdot \cfrac{\underline{day}}{24~\underline{hr}}\cdot \cfrac{\underline{hr}}{60~min}\implies \cfrac{3500000~deaths}{365\cdot 24\cdot 60~min} 
\\\\\\
\cfrac{3500000~deaths}{525600~min}\qquad \approx \qquad 6.6590563~\frac{deaths}{min}$

8 0

3 years ago

X is on line WY. Find the value of b.

o-na [289]

The answer is 85

explanation: x=180

now you just have to subtract 85 from 180 and you get 85

8 0

2 years ago

Read 2 more answers

One day, a person went to a horse racing area. Instead of counting the number of humans an horses, he conuted 74 heads and 196 l

Komok [63]

A human has 1 head and 2 legs.
A horse has 1 head and 4 legs.

Let's make two equations from what we know.

There were a total of 74 heads.
There were a total of 196 legs.

Let's call humans 'x' and horses 'y'

The total number of heads were 74.
Humans have 1 head, and so do horses.

Our first equation is:
x + y = 74

There were a total of 196 legs.
Humans have 2 legs, and horses have 4 legs.

Our second equation is:
2x + 4y = 196

Our two equations are:

x + y = 74
2x + 4y = 196

We need to solve this system of equations to find out how many humans and horses were at this racing event.

Multiply the first equation by 2.

2(x + y) = 2(74)
2x + 2y = 148

Our two equations are:

2x + 2y = 148
2x + 4y = 196

Subtract the first equation from the second equation.

2x - 2x + 2y - 4y = 148 - 196
2y - 4y = 148 - 196
-2y = - 48

Divide both sides by -2

y = 24

That means that there were 24 horses.

We can plug back in y = 24 into our first equation to find out how many humans there were.

x + y = 74
x + 24 = 74
x + 24 - 24 = 74 - 24
x = 50

There were 50 humans.

At the horse racing event, there were 24 horses and 50 humans.

Your final answer is B. 24 horses and 50 humans.

7 0

3 years ago

Read 2 more answers

It cost Evan $17.70 to send 177 text messages how many text messages did he send if he spent $19.10

tatuchka [14]

He sent 191 text messages

3 0

3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago