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Nookie1986 [14]
2 years ago
11

Rita started to run on a treadmill after setting its timer for 93 minutes. The display says that she has finished 24% of her run

. How many minutes have gone
by? Round your answer to the nearest tenth.
1 minutes
5
?
Mathematics
1 answer:
Alexxx [7]2 years ago
8 0

Answer

22

Step-by-step explanation:

24%=24/100, she finished 24% of her run and of means to multiply so 24/100 x93= 22.32. 22.32 rounded to the nearest tenth is 22 so 22 minutes is the amount of time that has gone by :)

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What is the Bill of Rights?
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The list of laws that people of the United Stated needed to follow

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2 years ago
Find the sum of the first six terms of the sequence.<br><br><br> S6 = ⇒ 84
k0ka [10]

Answer:

Explained below.

Step-by-step explanation:

Consider the series is a set of first 6 natural numbers.

Sum of first <em>n</em> terms is:

\text{Sum of n terms}=\frac{n(n+1)}{2}

\text{Sum of first 6 terms}=\frac{6(6+1)}{2}

                               =3\times7\\=21

Consider the series is an arithmetic sequence.

Sum of first <em>n</em> terms is:

S_{n}=\frac{n}{2} [2a+(n-1)d]

Here<em>,</em>

<em>a</em> = first term

<em>d</em> = common difference

Consider the series is an geometric sequence.

Sum of first <em>n</em> terms is:

S_{n}=\frac{a_{1}\cdot(1-r^{n})}{(1-r)}

Here<em>,</em>

<em>a₁</em> = first term

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7 0
2 years ago
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

4 0
2 years ago
a (1,4) b (-1,2) c (5,-2) are the vertices of triangle abc find the sum of coordinates of the point where the right bisector of
zmey [24]

Answer:

3.

Step-by-step explanation:

Find the midpoint of BC:

midpoint = (-1+5)/2, (2-2)/2 = (2, 0).

The slope of BC = (2 - -2) / (-1-5) = -2/3.

Find the equation of the right bisector of BC:

The slope = -1 / -2/3 = 3/2.

y-y1 = m(x-x1)

y - 0 = 3/2(x - 2)

y = 3/2x - 3.

Now find the equation of the median through C:

The midpoint of AB = (1 - 1)/2, (4+2)/2

= (0, 3).

The equation of the median:

The slope = (-2-3) / (5-0)

= -1.

The equation is:

y - 3 = -1(x - 0)

y -3 = -x.

Now we find the point of intersection by solving the 2 equations:

y - 3 = -x

y = 3/2x - 3

y = -x + 3

So:

3/2x - 3 = -x + 3

3/2x + x = 6

5/2 x = 6

x = 12/5.

y =  -12/5 + 3

= -12/5 + 15/5

= 3/5.

The sum of the coordinates = 12/5 + 3 /5

= 15/5

= 3.

3 0
3 years ago
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