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Inessa05 [86]
3 years ago
5

Solve by completing the squarex squared +14x - 51=0

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
x^2 +14x - 51=0\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3


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Similarly, the distance of a point (x_0,y_0) from the x-axis can be written as

d_x=|y_0|

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

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d_B = |a| = a

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Learn more about distance:

brainly.com/question/3969582

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