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3 years ago

Two lines, A and B, are represented by the following equations:

Mathematics

2 answers:

borishaifa [10]3 years ago

7 0

Answer:

The answer is B! if you want to do more of these problems may I recommend using Desmos?

lbvjy [14]3 years ago

6 0

Answer:

It is (2, 2).

Step-by-step explanation:

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What fraction of a year is 285 days

guapka [62]

Your answer will be <span>9 Months 15 days hope this helps</span>

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3 years ago

A 3 lb bag of one brand of cat food costs $3.52. A 6 lb bag of another brand costs $6.80. Which brand is cheaper per pound?

Illusion [34]

A 6 lb bag of another brand

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3 years ago

Read 2 more answers

Which one do I put in the first and second box?

Mademuasel [1]

Answer:

1000 : 10

Step-by-step explanation:

1 cm = 0.01 m

10 000 cm = 10 000 * 0.01 m = 100m

so the answer is 1000 : 10.

7 0

3 years ago

Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.

Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

$P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}$

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

$P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}$

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

$P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420$

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0

3 years ago

Find the values of the ratios

OleMash [197]

Answer:

perimeter: 5/8
area: 25/64

Step-by-step explanation:

You want the ratios (red to blue), of perimeter and area, given that corresponding sides have the ratio red to blue = 5 to 8.

<h3>Perimeter ratio</h3>

The ratio of perimeters is the ratio of corresponding side lengths:

red to blue = 5 / 8

<h3>Area ratio</h3>

The ratio of areas is the square of the ratio of corresponding side lengths:

red to blue = (5 to 8)² = 25 / 64

<em>Additional comment</em>

Ratios are customarily expressed in any of three equivalent forms:

5 to 8
5:8
5/8 "fraction" form

3 0

1 year ago