Complete Question:
The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel? Recall that the radius of the sphere is about 0.312 m. Express your answer with three significant figures in Kg.m².
Answer:
I = 5.88*10⁻³ kg.m²
Explanation:
It can be showed that the rotational inertia (or moment of inertia) for a solid sphere of radius r and mass m, regarding any axis passing through the center of the sphere, can be expressed as follows:
I = (2/5)*m*r² (1)
where m= 0.151 kg, and r =0.312 m. (Our givens).
Replacing in (1) we have:
I = (2/5)*0.151 kg*(0.312m)² = 5.88*10⁻³ kg.m²
I believe the energy being described is the potential energy. Potential energy is the stored energy, it is the energy an object has because of its position or shape. It is also the energy possessed by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. The major types of energy include the gravitational energy of an object that depends on its mass and its distance from the center of mass.
the answer to the question is a metallic conductor with free electrons surrounded by a rubber insulator lacking free electrons
The person must stand at a radius of 0.99 m
Explanation:
In order for the person to stand on the merry go round, the force of friction acting on the person must provide the centripetal force necessary to keep the person in uniform circular motion.
Therefore, we can write:

where:
- the term on the left is the force of friction, and the term on the right is the centripetal force
is the coefficient of friction
m is the mass of the person
is the acceleration of gravity
is the angular velocity
r is the radius of the circular path
Solving the equation for r, we find the radius at which the person must be standing:

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