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sasho [114]
3 years ago
10

Write S if the given quantity is scalar and V if the quantity is a vector

Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

1. Scalar_100° Celsius

2. Vector_50 m/s²

3. Scalar_300 s

4. Vector_250 m/s, northwest

5. Vector_1m, to the right

6. Vector_10 cm, upwards

7. Scalar_525 600 mins.

8. Vector_90 km/h,east

8. Scalar_5 000 kg

10. Scalar_1.5 L

Explanation:

A scalar quantity can be defined as a quantity that has magnitude but no direction. Some examples of scalar quantities are speed, mass, temperature, volume, length, etc.

On the other hand, a vector quantity has both magnitude and direction. Some examples of vector quantities are acceleration, velocity, displacement, etc.

1. Scalar_100° Celsius (Temperature).

2. Vector_50 m/s² (Acceleration).

3. Scalar_300 s (Time).

4. Vector_250 m/s, northwest (Velocity).

5. Vector_1m, to the right (Displacement).

6. Vector_10 cm, upwards (Displacement).

7. Scalar_525 600 mins. (Time).

8. Vector_90 km/h,east (Velocity).

8. Scalar_5 000 kg (Mass).

10. Scalar_1.5 L (Volume).

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An electric motor rotating a workshop grinding wheel at a rate of 151 rev/min is switched off. Assume constant angular decelerat
tamaranim1 [39]

Answer:

Explanation:

Initial angular velocity ω₀ = 151 x 2π / 60

= 15.8  rad /s

final velocity = 0

Angular deceleration α = 2.23 rad / s

ω² = ω₀² -  2 α θ

0 = 15.8² - 2 x 2.23 θ

= 55.99  rad

one revolution = 2π radian

55.99 radian = 55.99  / 2 π no of terns

= 9 approx .

8 0
3 years ago
A projector is placed on the ground 22 ft. away from a projector screen. A 5.2 ft. tall person is walking toward the screen at a
Stella [2.4K]

Answer:

y = 67.6 feet,   y = 114.4/ (22 - 3t)

Explanation:

For this exercise let's use that light travels in a straight line and some trigonometric relationships, the symbols are in the attached diagram

Large triangle Projector up to the screen

         tan θ = y / L

For the small triangle. Projector up to the person

         tan θ = y₀ / (L-d)

The angle is the same, so we equate the two equations

         y₀ / (L -d) = y / L

         y = y₀  L / (L-d)

The distance from the screen (d), we look for it with kinematics

         v = d / t

        d = v t

we replace

         y = y₀ L / (L - v t)

         y = 5.2 22 / (22 - 3 t)

         y = 114.4 (22 - 3t)⁻¹

This is the equation of the shadow height change as a function of time

For the suggested distance the shadow has a height of

           y = 114.4 / (22-13)

           y = 67.6 feet

7 0
3 years ago
Which point on the standing wave is a node?
Digiron [165]

Answer: it’s c

Explanation: ap3x

8 0
2 years ago
Read 2 more answers
How can you tell that toast is not warmed up by conduction?
solmaris [256]

Answer:

Toasting in a toaster is usually considered  by (infra red) radiation. But the hot coils touch the toast so an element of heating by conduction occurs as well.

Explanation:

8 0
2 years ago
A wire 95.0 mm long is bent in a right angle such that the wire starts at the origin and goes in a straight line to x = 40.0 mm
qaws [65]

Answer:

0.1040512455 N

36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

0.05925 N

29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

Explanation:

I = Current

B = Magnetic field

Separation between end points is

l=\sqrt{40^2+55^2}\\\Rightarrow l=68.00735\ mm

Effective force is given by

F=IlB\\\Rightarrow F=5.1\times 68.00735\times 10^{-3}\times 0.3\\\Rightarrow F=0.1040512455\ N

The force is 0.1040512455 N

tan\theta=\dfrac{55}{40}\\\Rightarrow \theta=tan^{-1}\dfrac{55}{40}\\\Rightarrow \theta=53.97^{\circ}

The angle the force makes is given by

\alpha=\theta-90\\\Rightarrow \alpha=53.97-90\\\Rightarrow \alpha=-36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

The direction is 36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

F=IlB\\\Rightarrow F=4.9\times \sqrt{20^2+35^2}\times 10^{-3}\times 0.3\\\Rightarrow F=0.05925\ N

The force is 0.05925 N

tan\theta=\dfrac{35}{20}\\\Rightarrow \theta=tan^{-1}\dfrac{35}{20}\\\Rightarrow \theta=60.26^{\circ}

\alpha=\theta-90\\\Rightarrow \alpha=60.26-90\\\Rightarrow \alpha=-29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

The direction is 29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

4 0
2 years ago
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