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3 years ago

WHAT IS THE ANSWER PLZ HELP ME??? I WILL MARK BRAINLIEST!!!

Mathematics

2 answers:

Anestetic [448]3 years ago

5 0

Answer:

- 5/6

Step-by-step explanation:

turn it into an improper fraction.

1 and 2/3 = 5/3

2 and 1/2 = 5/2

5/3 - 5/2 = 10/6 - 15/6

= -5/6

Vitek1552 [10]3 years ago

4 0

Answer:

First you have to change both of the mixed numbers to improper fractions. To do this you would multiply the denominator and the whole number then add the numerator.

1 2/3 = 5/3

-2 1/2 = -5/2

Find the least common denominator (LCM). Add the numerator, and keep the denominator the same.

The LCM for these two fractions would be 6 so to get to six you would multiply 5/3 by 2/2 and -5/2 by 3/3.

5/3 = 10/6

-5/2 = -15/6

Add the numerators (10 + -15 = -5), and keep the denominator the same (6). Therefore, the answer would be -5/6.

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Evelyn says that the equation 3(x - 3) + 5 = 3x + 1 + 4

Alex787 [66]

Step 1: Simplify both sides of the equation.

3(x−3)+5=3x+1+4

(3)(x)+(3)(−3)+5=3x+1+4(Distribute)

3x+−9+5=3x+1+4

(3x)+(−9+5)=(3x)+(1+4)(Combine Like Terms)

3x+−4=3x+5

3x−4=3x+5

Step 2: Subtract 3x from both sides.

3x−4−3x=3x+5−3x

−4=5

Step 3: Add 4 to both sides.

−4+4=5+4

0=9

8 0

3 years ago

In the local frisbee league, teams have 7 members and each of the 4 teams takes turns hosting tournaments. At each tournament, e

mars1129 [50]

There are 4 teams in total and each team has 7 members. One of the team will be the host team.

Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.

So total number of possible 9 member tournament committees will be equal to:

$7C3 \times 7C2 \times 7C2 \times 7C2\\ \\ = 324135$

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

$9 \times 324135\\ \\ =2917215$

Therefore, there are 2917215 possible 9 member tournament committees

8 0

3 years ago

Dear Math Helper,

valentina_108 [34]

Answer:

n = 98, that is, she scored at the 98th percentile.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

She scored 38, so $X = 38$