Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third
1 answer:
Answer:
3, 5, 7
Step-by-step explanation:
1st number: (2k+1)
2nd number: (2k+3)
3rd number: (2k+5), k∈Z
3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)
3*(4k+4)=3+6k+15
12k+12=18+6k
6k=6
k=1
1st number: (2k+1) = 3
2nd number: (2k+3)=5
3rd number: (2k+5)=7
You might be interested in
100 and 101
the two integers are n and n+1. this means that 2n+1=201. n=100 and n+1=101
Simply move -2 to another side.
Distribute -1/3 in (x+6)
---> Answer
Answer:
1. They consist primarily of variables.
2. They are often called formulas.
4. They often describe real-world relationships.
Answer:
300
Step-by-step explanation:
2*60 for 1 hr
120*2 to find two hrs
2*30 for 1/2 hr
add
Answer:
week mo naman salamat sa points
