Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third
1 answer:
Answer:
3, 5, 7
Step-by-step explanation:
1st number: (2k+1)
2nd number: (2k+3)
3rd number: (2k+5), k∈Z
3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)
3*(4k+4)=3+6k+15
12k+12=18+6k
6k=6
k=1
1st number: (2k+1) = 3
2nd number: (2k+3)=5
3rd number: (2k+5)=7
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