Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third
1 answer:
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Answer - (-2, 2)
Explanation - Difference of coordinates:
Δx = 2 - (-4) = 6
Δy = - 8 - 7 = - 15
The ratio of AB to AC is 2:1. So:
AB = 2*AC/3 and BC = AC/3
Then coordinates of point B should be 2/3 from the point A:
x = 2- 6*2/3 = 2 - 4 = -2
y = - 8 - (-15)*2/3 = -8 + 10 = 2
So point B has coordinates of (-2, 2)
Explanation - Difference of coordinates:
Δx = 2 - (-4) = 6
Δy = - 8 - 7 = - 15
The ratio of AB to AC is 2:1. So:
AB = 2*AC/3 and BC = AC/3
Then coordinates of point B should be 2/3 from the point A:
x = 2- 6*2/3 = 2 - 4 = -2
y = - 8 - (-15)*2/3 = -8 + 10 = 2
So point B has coordinates of (-2, 2)