Question

Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

Answer 1

Answer:

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)

3*(4k+4)=3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3)=5

3rd number: (2k+5)=7