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seraphim [82]
3 years ago
11

Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer:

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)

3*(4k+4)=3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3)=5

3rd number: (2k+5)=7

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Murljashka [212]
4-1/2x=10
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3
so your answer would be B
hope that helps
7 0
3 years ago
One number exceeds another by 24. The sum of the numbers<br> is 58. What are the numbers?
Anna35 [415]
X + x + 24 = 58
x = (58-24)/2=17
the first number is 17 and the second number is the sum of 17 and 28. Finding it has been left as an exercise for the reader.
3 0
3 years ago
12.03,1.2,12.3,1.203,12.301 order least to greatest
m_a_m_a [10]

Answer:

1,2, 1,203, 12,03, 12,3, 12,301

Step-by-step explanation:

1,2 → 1,200

1,203

12,3 → 12,300

12,301

I am joyous to assist you anytime.

8 0
4 years ago
If a drug has a concentration of 400 mg per 10 ml, how many mL are needed to give 1.5 grams of the drug?
liq [111]

40,

since

400 x 4 + 1.6 grams. which is the closest

4 x 10 = 40

4 0
4 years ago
If f(x)=x^2+2x-10, what is f(-2)?<br><br>-10<br>-16<br>-18<br>-2
adell [148]
F(x)=x^2+2x-10
f(-2)=4-4-10
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the answer is A) or -10
8 0
3 years ago
Read 2 more answers
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