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Karolina [17]
3 years ago
7

2x^(2)+12x+8 using completing square

Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

{2x}^{2}  + 12x + 8 \\  =  {x}^{2}  + 6x + 4 \\  =  {x}^{2}  + 6x +  {( \frac{6}{2}) }^{2}  + 4 -  {( \frac{6}{2} )}^{2}  \\  = ( {x}^{2}  + 6x +  {3}^{2} ) + ( - 5) \\  =  {(x + 3)}^{2}   - 5

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my final balance after 48 months was 896.00 if i originally put 800.00 into the bank what was the interest rate
Tems11 [23]
48 - 896.00 = 884
884-800=84
so the interest rate was 84

7 0
3 years ago
K+2 over 3= -7 <br> How do u solve this problem
harkovskaia [24]
K+2/3=-7
K+2=-7x3
K+2=-21
K=-19
3 0
3 years ago
What is ¨0.83% of n is 18.26¨ (just tell me the value of n)
jolli1 [7]

Answer:

<h2>N = 2,200</h2>

'Percent (%)' means 'out of one hundred':

0.83% = 0.83 'out of one hundred',

p% is read p 'percent',

0.83% = 0.83/100 = 0.83 ÷ 100

Calculate percentage:

'Percentage' is obtained by multiplying 2,200 by 0.83%

0.83% × 2,200 =

(0.83 ÷ 100) × 2,200 =

(0.83 × 2,200) ÷ 100 =

1,826 ÷ 100 =

18.26

Step-by-step explanation:

Hope it is helpful....

5 0
3 years ago
Craig is standing on his apartment balcony and locates his car in the street-level parking lot below. The angle of depression of
murzikaleks [220]

Answer:

B. 147 feet

Step-by-step explanation:

We can easily imagine a right triangle for this problem. The height of the triangle is what we're looking for (x), at the bottom of x, we have the right angle formed by the building and the ground.  The other side of that right angle is the distance to the car (300 ft). On top of the x side, we have the angle of 63 degrees looking down, since Craig is looking down by 27 degrees (90 - 27 = 63).

We can easily apply the Law of Sines that says:

\frac{a}{sin(A)} = \frac{c}{sin(C)}

Then we can isolate c and fill in the values:

c = \frac{a * sin(C)}{sin(A)} =\frac{300 * sin(27)}{sin(63)} = 153

So, we know Craig's eyes are 153 feet above ground... since Craig is 6 feet tall, the balcony sits at 147 feet high (153 - 6 = 147).

6 0
3 years ago
I need to find two consecutive positive integers such that the square of the first is decreased by 17 equals to 4 times the seco
aleksandrvk [35]
So, is two integers, and they must be consecutive, meaning, the next one will have to be either 1 before the first or one after... anyhow.

let's say the first integer is "a".

then a consecutive integer to that one will be just 1 hop away, or say "a + 1", so there, those are the two integers.

now, we know that 

\bf \stackrel{\textit{square of the first is decreased by 17}}{a^2-17}~~=~~\stackrel{\textit{4 times the second}}{4(a+1)}&#10;\\\\\\&#10;a^2-17=4a+4\implies a^2-4a-21=0\implies (a-7)(a+3)=0&#10;\\\\\\&#10;a=&#10;\begin{cases}&#10;\boxed{7}\\&#10;-3&#10;\end{cases}

so, is a positive integer, so it can't be -3.

what's the second integer?  well is a + 1.
5 0
3 years ago
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