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djyliett [7]
3 years ago
13

About 5 - 6% of the student population has more than 3 pets. If the student population is 450 people, how many would have more t

han 3 pets?
PLEASE HELP ME PLLLEASEEEEEEEEE
Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

23-27 students makes up the popuation of the 5-6%

Step-by-step explanation:

450*.05= 22.5

450*.06= 27

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I believe the answer is $17.50, she earned $30 off of $600 meaning she had a 5% interest rate and 5% of 350 is $17.50
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4 years ago
A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
amm1812

Answer:

Given:

Sham: n= 20,     x=0.44,   s=1.24,

Magnet:n= 20,  x =0.49,   s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

\frac{s1^2}{s2^2}

\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom = n - 1 = 20 - 1 = 19

Magnet: degrees of freedom = n - 1 = 20 - 1 = 19

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]

f[0.025, 19, 19], f[0.975, 19, 19]

(2.526, 0.3958)

The rejection region:

Reject H0, if  F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0
3 years ago
a jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30 east of north. how far is he from his house a
Jobisdone [24]
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x       eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1)      eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
5 0
3 years ago
In AQRS, m2 Q = 63º, mZ R = 70°, and m2 S= 47°. Which side of AQRS is the
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Answer:

D. QR.

Step-by-step explanation:

1) in ΔQRS the side QR is opposite the angle S (47°); QS is opposite the angle R (70°); RS is opposite the angle Q (63°);

2) the rule is: greater angle is opposite the longer side;

3) according to the rule the angle 'S' is the smallest, then the side QR is the shortest.

5 0
3 years ago
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