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3 years ago

Is this wave perpendicular or parallel?

Physics

2 answers:

mote1985 [20]3 years ago

6 0

Answer:

I think it is Perpendicular

Alenkinab [10]3 years ago

4 0

Answer:

Perpendicular

Explanation:

In the image is seems to be that it's a transverse wave and transverse waves travel in a direction perpendicular to the direction that this wave moves.

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Can someone please help on this one?

zhuklara [117]

Please READ Newton's first law of motion, and you'll see how nicely it explains that fact.

8 0

4 years ago

Two obiect accumulated a charge of

tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

$q_1=4.5\mu C=4.5\cdot 10^{-6}C$ is the magnitude of the 1st charge

$q_2=2.8\mu C=2.8\cdot 10^{-6}C$ is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

$F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N$

So, the closest answer is

A) 181.24 N

3 0

4 years ago

A buoy, floating in a ripple tank, is at rest when a wave reaches it. The wave has a frequency of 1.25 Hz, and an amplitude of 0

sergey [27]

Answer:

y = -6.57 10⁻³ m

Explanation:

The movement of water is an oscillation in the vertical direction that can be approximated as a simple harmonic movement

y = A cos (wt)

where the amplitude is A = 0.75 m and the angular velocity is related to the frequency

w = 2π f

w = 2π 1.25

w = 7.85 rad / s

we substitute

y = 0.75 cos (7.85 t)

we look for the amplitude for a time of t = 2.20 s, remember that the angles are in radians

y = 0.75 cos (7.85 2.20)

y = -0.00657 m

y = -6.57 10⁻³ m

5 0

3 years ago

3. When a magnetic sector instrument was operated with an accelerating voltage of 4.50*103 V, a field of 0.251 T was required to

Damm [24]

Answer:

The answer is " $4,500 - 225 \ V$ ".

Explanation:

Using formula for calculating the Voltage:

$M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\$