The ability to sustain life
(ie water, shelter, food, basic needs)
Hope this helped!
:-)
Answer:
i. Cv =3R/2
ii. Cp = 5R/2
Explanation:
i. Cv = Molar heat capacity at constant volume
Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT
Differentiating U with respect to T, we have
= d(3/2RT)/dT
= 3R/2
ii. Cp - Molar heat capacity at constant pressure
Cp = Cv + R
substituting Cv into the equation, we have
Cp = 3R/2 + R
taking L.C.M
Cp = (3R + 2R)/2
Cp = 5R/2
Answer:
Electric field, E = 0.064 V/m
Explanation:
It is given that,
Resistivity of silver wire, ![\rho=1.59\times 10^{-8}\ \Omega-m](https://tex.z-dn.net/?f=%5Crho%3D1.59%5Ctimes%2010%5E%7B-8%7D%5C%20%5COmega-m)
Current density of the wire, ![J=4\ A/mm^2=4\times 10^6\ A/m^2](https://tex.z-dn.net/?f=J%3D4%5C%20A%2Fmm%5E2%3D4%5Ctimes%2010%5E6%5C%20A%2Fm%5E2)
We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :
![E=J\times \rho](https://tex.z-dn.net/?f=E%3DJ%5Ctimes%20%5Crho)
![E=4\times 10^6\times 1.59\times 10^{-8}](https://tex.z-dn.net/?f=E%3D4%5Ctimes%2010%5E6%5Ctimes%201.59%5Ctimes%2010%5E%7B-8%7D)
E = 0.0636 V/m
or
E = 0.064 V/m
So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.
Diffuse reflection have a great day