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VladimirAG [237]
3 years ago
8

Which is true regarding AC current? The electrons move back and forth. The +/- polarity is constant. It is common in portable de

vices. It can only produce low voltages.
Physics
2 answers:
Rus_ich [418]3 years ago
8 0
A. The electrons move back and forth.
Hope this helped. :L
andre [41]3 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

AC current stands for alternating current. In an alternating current there is periodically reverse movement of current.

This means electrons move in one direction for a certain time and then they reverse their movement for the same time period and it continues in the back and forth position.

Thus, we can conclude that the statement electrons move back and forth is true regarding AC current.


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Identifying Advantages of Parallel Circuits
melisa1 [442]

Answer: If one bulb goes out the other bulbs stay lit.

If there is a break in one branch of the circuit, current can still flow through the other branches.

Explanation:

3 0
3 years ago
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6.If a 250. gram cart moving to the right with a velocity of .31 m/s collides inelastically with a 500. gram cart traveling to t
spin [16.1K]

Answer:

The total momentum of the system before the collision is 0.0325 kg-m/s due east direction.    

Explanation:

Given that,

Mass of the cart, m = 250 g = 0.25 kg

Initial velocity of the cart, u = 0.31 m/s (due right)

Mass of another cart, m' = 500 g = 0.5 kg

Initial velocity of the another cart u' = -0.22 m/s (due left)

Let p is the total momentum of the system before the collision. It is given by :

p=mu+m'u'\\\\p=0.25\times 0.31+0.5\times (-0.22)\\\\p=-0.0325\ kg-m/s

So, the total momentum of the system before the collision is 0.0325 kg-m/s due east direction.            

5 0
3 years ago
Read 2 more answers
What r three positive results of a variation within a population that occur due to natural selection
Phoenix [80]

Answer:

Traits, evolution, adaptive

4 0
3 years ago
Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
Ket [755]

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

Find:

a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

5 0
4 years ago
A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
Yakvenalex [24]

Answer:

Centripetal acceleration

Explanation:

  • The centripetal acceleration is the motion inwards towards the center of a circular path.
  • <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path. </u></em>
  • That is;

         ac = v²/r

         Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the  radius, m

3 0
3 years ago
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