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steposvetlana [31]
11 months ago
13

Find the electron and hole concentrations and fermi level in silicon at 300 k for boron

Physics
1 answer:
gogolik [260]11 months ago
4 0

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x 10^4 cm^-3.

<h3>Calculation and Explanation</h3>

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at 10^{15} cm^{-3} (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = 10^{15} cm^{-3}

np = \frac{ni^2}{nA}

np = \frac{(9.65 x 10^9)^2}{10^15}

np= 9.3 x 10^4 cm^-3

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x 10^{19} / 10^{15} )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

To know more about ionization energy, visit:

brainly.com/question/16243729

#SPJ4

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Answer:

the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1

Explanation:

Given the data in the question;

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Mass_{Hank × Acceleration_{Hank = Mass_{Henry × Acceleration_{Henry

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Mass_{Hank /  Mass_{Henry = Acceleration_{Henry / Acceleration_{Hank

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Mass_{Hank /  Mass_{Henry = 0.7937 or [ 0.7937 : 1 ]

Therefore, the ratio of Hank's mass to Harry's mass is 0.7937 or [ 0.7937 : 1 ]

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What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subs
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The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

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The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

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An electron, moving south, enters a uniform magnetic field. Because of this uniform magnetic field, the electron curves upward.
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Magnetic force is given as

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V×B means the cross product of the velocity and the magnetic field

NOTE:

i×i=j×j×k×k=0

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So, if the electron is moving southward, then, it implies that the velocity of it motion is southward, so the electron is in the positive z-direction

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Then,

V = V•k

F = F•j

Then, apply the theorem

F •j = q ( V•k × B•x)

Let x be the unknown

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This shows that x = i

Then, the magnetic field point in the direction of positive x axis, which is towards the west

You can as well use the Fleming right hand rule

The thumb represent force

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gregori [183]

Explanation:

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