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Ulleksa [173]
3 years ago
14

A candy store sells caramels for $9/pound and chocolate for $12/pound. How much more is the cost of 2 pounds of caramel than 1.5

pounds of chocolate? *Show your work*
Mathematics
1 answer:
Rashid [163]3 years ago
5 0

Answer:

The caramel is $0 more than the chocolate. In other words, they cost the same.

Step-by-step explanation:

Since we have 2 pounds of caramel and caramel costs $9/pound, the cost of 2 pounds of caramel can be found by this equation:

2lbs · $9 = $18

Since we have 1.5 pounds of chocolate and chocolate costs $12/pound, the cost of 1.5 pounds of chocolate can be found by this equation:

1.5lbs · $12 = $18

To find how much bigger the cost of caramel is than that of chocolate, we will subtract the total cost of the chocolate from the total cost of the caramel.

$18 - $18 = $0

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Step-by-step explanation:

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6 0
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1.44 Make-up exam: In a class of 28 students, 27 of them took an exam in class and 1 student took a make-up exam the following d
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Answer:

a) Decrease

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c) Decrease                        

Step-by-step explanation:

We are given the following in the question:

Total number of students in class = 28

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Standard Deviation of 27 students = 6.5

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a) The new student's score will decrease the average.

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Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean = \dfrac{\displaystyle\sum x_i}{27} = 79\\\\\sum x_i = 27\times 79 = 2133

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\text{ New mean} =\dfrac{ \displaystyle\sum x_i +63}{28}\\\\ =\dfrac{2133+63}{28}= \dfrac{2196}{28} = 78.43

Thus, the new mean is 78.43

c) Since the new mean decreases, standard deviation for new scores will decrease.

This is because the new value is within the usual values i.e. within two standard deviations of the mean. So, this wont cause a lot of variation as this value will be closer to already available data values. Also number of observations (n) in the denominator is increasing. Based on both these points we can conclude that standard deviation will decrease

Formula for Standard Deviation:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

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Step-by-step explanation:

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