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Ulleksa [173]
2 years ago
14

A candy store sells caramels for $9/pound and chocolate for $12/pound. How much more is the cost of 2 pounds of caramel than 1.5

pounds of chocolate? *Show your work*
Mathematics
1 answer:
Rashid [163]2 years ago
5 0

Answer:

The caramel is $0 more than the chocolate. In other words, they cost the same.

Step-by-step explanation:

Since we have 2 pounds of caramel and caramel costs $9/pound, the cost of 2 pounds of caramel can be found by this equation:

2lbs · $9 = $18

Since we have 1.5 pounds of chocolate and chocolate costs $12/pound, the cost of 1.5 pounds of chocolate can be found by this equation:

1.5lbs · $12 = $18

To find how much bigger the cost of caramel is than that of chocolate, we will subtract the total cost of the chocolate from the total cost of the caramel.

$18 - $18 = $0

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In the following monomial, what is the 5 called?
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Answer:

<em><u>5 is called coefficient</u></em>

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<em><u>3 is called degree....</u></em>

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A new cereal will be advertised in 30-second spots during a morning TV show for children. The ad will run over the next 60 days.
Arturiano [62]
The campaign will cost $216,000
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Find the value of x. (Type an integer or decimal.)
SOVA2 [1]

Answer:

70

Step-by-step explanation:

An angle formed by 2 tangent lines is equal to one half the measure of the major arc minus the measure of the minor arc.

we are given the minor arc ( 110 ) however we are not given the major arc.

Because circles make a 360 degree rotation we can find the major arc by subtracting the measure of the minor arc from 360

Thus, major arc = 360 - 110 = 250

Now that we have identified the major and minor arc we can find x

Recall that x = 1/2 ( major arc - minor arc )

Thus, x = 1/2 ( 250 - 110 )

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Hence, x = 70

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2 years ago
Solve and simplify, typing the final answer as a fraction 1/4 ÷ 3/8
natita [175]

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Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling
arlik [135]

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

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  • W = weight of particle = mg where
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  • g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

  • T' = tension in chain and
  • T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

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