The answer to the question is c
For this problem, here’s how you do it.
Answer:
○ 
Step-by-step explanation:
![\displaystyle 6m^3 - 60m^2 + 144m \\ 6m[m^2 - 10m + 24m] \\ \\ \boxed{6m[m - 4][m - 6]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%206m%5E3%20-%2060m%5E2%20%2B%20144m%20%5C%5C%206m%5Bm%5E2%20-%2010m%20%2B%2024m%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B6m%5Bm%20-%204%5D%5Bm%20-%206%5D%7D)
I am joyous to assist you at any time.
Answer:
Last option: increasing: -2 < x < 0 and x> 3/2;
decreasing: x < -2 and 0 < x < 3/2
Step-by-step explanation:
The function given is an absolute cubic function. (Pictured below).
We can determine from the graph that the equation increases over the interval:
increasing: -2 < x < 0 and x> 3/2;
decreasing: x < -2 and 0 < x < 3/2
Answer:
21% probability you will hit a green light on monday and a red light on tuesday
Step-by-step explanation:
When two events, A and B, are independent, we have that:

In this problem, we have that:
Event A: Green light on monday.
Event B: Red light on tuesday.
The probability that we encounter a green light at the corner of college and main is 0.35
This means that 
The probability that we encounter a red light is 0.61:
This means that 
These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So

21% probability you will hit a green light on monday and a red light on tuesday