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nignag [31]
2 years ago
8

BRAINLIEST AND 50 POINTS GET IT QUICK

Mathematics
2 answers:
baherus [9]2 years ago
7 0

Answer:

It travels for 3 hours, then stops for 1 hour, and finally travels again for 1 hour.

Step-by-step explanation:

<em>Sorry I'm late</em>

<em>(I got it right on my FLVS test)</em>

sergeinik [125]2 years ago
6 0

Answer:

It travels for 2 hours, then stops for 1 hour, and finally travels again for 5 hours.

Step-by-step explanation:

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Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,
Bas_tet [7]

Answer:

a) \bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

Median = 25

b) Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) Midrange = \frac{70+13}{3}=41.5

d) Q_1 = \frac{20+21}{2} =20.5

Q_3 =\frac{35+35}{2}=35

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

Median = 25

Part b

The mode is the most repeated value on the dataset on this case would be:

Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

Midrange = \frac{Max+Min}{2}

And if we replace we got:

Midrange = \frac{70+13}{3}=41.5

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

Q_1 = \frac{20+21}{2} =20.5

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

Q_3 =\frac{35+35}{2}=35

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0
3 years ago
Question 8
yanalaym [24]
Answer: use google dot com
7 0
2 years ago
Michaels buys three over a pound of cheese he puts the same amount of cheese and three sandwiches how many cheese how much chees
Tasya [4]

Question is not proper,Proper question is given below;

Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich

Answer:

Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

Step-by-step explanation:

Total Amount of cheese he has = \frac{3}{8} \ pound

Number of cheese sandwiches = 3

We need to find Amount of cheese does Nicole put on each of his sandwich.

Solution:

Amount of cheese on each sandwich can be calculated by dividing Total Amount of cheese he has with Number of cheese sandwiches.

framing in equation form we get;

Amount of cheese on each sandwich = \frac{\frac{3}{8}}{3}} = \frac{1}{8} \ pounds

Hence Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

7 0
3 years ago
A 3-ounce serving of tuna provides 21 g of protein use equivalent ratios to find how many grams of protein are in 9 ounces of tu
cluponka [151]
Since 3 ounces=21 g of protein, you would multiply 21 g x 3, because 6 ounces would = 42g. using that principle 3×3 = 9 & 21×3 = 63.
4 0
3 years ago
110,411 in expanded form
Neporo4naja [7]
One hundred and ten thousand , four hundred and eleven

11000 + 400 +11
5 0
3 years ago
Read 2 more answers
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