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3 years ago

Define frequency in your own words

Physics

1 answer:

defon3 years ago

7 0

Answer:

its the number of something repeating,

For example, a human heart may beat at a frequency of 68 beats per minute

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A particle moves in a circular path of radius 0.10 m with a constant angular speed of 5 rev/s. The acceleration of the particle

Darya [45]

Answer:

2.5 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s²

For circular motion, the expression for acceleration is given as,

a = ω²r ................ Equation 1

Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.

Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.

Substitute into equation 1

a = 5²(0.10)

a = 25(0.10)

a = 2.5 m/s²

Hence the acceleration of the particle = 2.5 m/s²

Hence, none of the option is correct

7 0

3 years ago

give three examples from the device on the apply page where potential energy was converted to kinetic energy

Elodia [21]

a water turbine drops water onto a blade which gains ke at water's gpe expense

4 0

3 years ago

A slide whistle is an open-closed tube with an adjustable plunger that changes the length. You are playing the slide whistle and

Serjik [45]

Answer:

df / ft = -n 12 n= 1, 3, 5, ...

Explanation:

The speed of sound is

v = λ f

In a whistle that we approach by an open tube at one end and closed at the other, standing waves occur, which has a node in the closed part and a maximum in the open pate, whereby wavelength and the distance of the tube are related, the fundamental wave is

λ₁ = 4L

The harmonics are

λ₃ = 4L / 3

λ₅ = 4L / 5

The general formula

λₙ = 4L / n

with n = 1, 3, 5,…

We substitute and clear in the first equation

f = v n / 4L n = 1, 3, 5,…

Let's use derivatives to find the frequency change

df / dt = v n /4 dL⁻¹ / dt

d / dt (1/L) = - 1 / L² dL / dt

Where dL / dt = 8 cm / s

We replace

df / dt = - n v / L2 dL / dt

Let's calculate

df / dt = - n 340/152 8

df / ft = -n 12 n= 1, 3, 5, ...

4 0

3 years ago

A rock is thrown vertically upward from the origin of a reference frame. The rock reaches the peak of its trajectory and then it

Tema [17]

Answer:

The acceleration of the rock is negative throughout the whole motion. (TRUE)

The acceleration of the rock is zero at the peak of the trajectory (FALSE)

The velocity of the rock is positive throughout the whole motion (FALSE)

The position of the rock is positive or zero throughout the whole motion (TRUE)

The velocity of the rock is positive throughout the whole motion (FALSE)

Explanation:

1)The acceleration of the rock is negative throughout the whole motion. (TRUE)

Using the upward direction as positive

Then, The acceleration of the rock is negative throughout the whole motion.

2)The acceleration of the rock is zero at the peak of the trajectory.(FALSE)

Only the velocity can be zero at the peak the trajectory, the acceleration is not zero

3)The velocity of the rock is positive throughout the whole motion (FALSE)

Using the upward direction as positive, The velocity of the rock is only positive when going in upward direction and vice versa

4)The position of the rock is positive or zero throughout the whole motion (TRUE)

When the rock get down it will have a zero position, then when it get to the peak it will have positive position

6 0

4 years ago

Need help asap if I fail this one I fail my grade so please tell me the right awser

bazaltina [42]

If you look up "distance vs time graph" you can pull up images on google and check them out. That's what I did and on the x-axis (horizontal line) it said "time." I'd go with time.

6 0

3 years ago