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mafiozo [28]
3 years ago
8

Define frequency in your own words

Physics
1 answer:
defon3 years ago
7 0

Answer:

its the number of something repeating,

For example, a human heart may beat at a frequency of 68 beats per minute

You might be interested in
Help
kenny6666 [7]

Sulfur trioxide

Carbon monoxide

Explanation:

  Molecule A is SO₃

  Molecule B is CO

SO₃ is sulfur trioxide formed usually by the reaction of SO₂ with oxygen. The bond type between the molecule is a covalent bond because two non-metals with low electronegativity differences are involved.

Here three oxygen atoms are attached to one sulfur atom.

CO is carbon monoxide. A poisonous gas with a wide range of industrial use. A covalent bond exists between the two atoms.

Learn more:

Molecules brainly.com/question/7213980

#learnwithBrainly

8 0
3 years ago
If an object has a volume of 2 milliliters and a mass of 10 grams, calculate the density of the object.
STatiana [176]
<span>Density = mass/volume 10g/2mL=5g/mL Atomic mass= protons + neutrons Atomic number=protons In a neutral atom, electrons = protons 15 amu-7 atomic number = 8 neutrons, 7 protons and 7 electrons</span>
7 0
3 years ago
Help me please I need to turn it in before midnight...
ale4655 [162]

Answer:

The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;

C. Increasing the angle from 25° to 50° will increase the total time spent in the air

Explanation:

The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;

T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}

Where;

T = The time of flight of the projectile = The time spent in the air

u = The initial velocity of the projectile

θ = The angle of launch of the projectile

g = The acceleration due to gravity ≈ 9.81 m/s²

Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;

Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;

T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}

sin(50°) > sin(25°), therefore, we have;

\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} >   \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

Therefore;

T₂ > T₁

Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.

7 0
3 years ago
If a ball is launched upward with a vertical velocity of 50 m/s and a horizontal velocity of 10 m/s, what will the vertical disp
Delicious77 [7]

Answer: The vertical displacement will be 127.5 meters

Step by step:

Since the question asks for the vertical displacement only, it is sufficient to limit our calculation to the vertical components of the problem.

We choose to measure the displacement on a vertical axis d with an initial coordinate 0 coinciding with the launch of the ball. There is an initial horizontal velocity v_0 of 50 m/s and the gravitational deceleration g acting in the direction opposite to the initial velocity. The formula for displacement of a body subject to an deceleration with an initial velocity (at time t=5 seconds) is:

d(t) = -\frac{1}{2}gt^2+v_0t+d_0=-\frac{1}{2}9.8 \frac{m}{s^2}t^2+50\frac{m}{s}\cdot t + 0m\\d(5) = -\frac{1}{2}9.8 \frac{m}{s^2}5^2 s^2+50\frac{m}{s}\cdot 5s=127.5m

After 5 seconds of the launch, the ball will be at the point 127.5 meters from the origin on the vertical axis (vertical displacement)


8 0
3 years ago
What does a metallurgist study
avanturin [10]
Metals and properties of metals.
3 0
4 years ago
Read 2 more answers
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