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Bess [88]
3 years ago
6

A conductor of uniform radius 1.20 cm carries a current of 3.00 A produced by an electric field of 120 V/m. What is the resistiv

ity of the material?
Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

The value is  \rho = 0.0180 97 9 \ \Omega m^{-1}

Explanation:

From the question we are told that

   The radius of the conductor is r = 1.20 \ cm = 0.012 \  m

    The current it is carrying is  I = 3.00 \ A

    The electric field is  E = 120 \  V/m

Generally the resistivity of the material is mathematically represented as

        \rho = \frac{EA}{ I }

Here A is the area of the conductor which is mathematically represented as

      A = \pi r^2

=>  A =3.142 *  (0.012)^2

=>  A =  0.000452 \ m^2

So

    \rho = \frac{120 * 0.000452}{ 3 }

=> \rho = 0.0180 97 9 \ \Omega m^{-1}

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