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Flauer [41]
3 years ago
14

What is homologous series. write the example. ​

Chemistry
1 answer:
Delvig [45]3 years ago
4 0
A homologous series is a succession of compounds with the exact same functional group and chemical properties that are alike in which the individuals of the series can be branched or even unbranched or contrast by -CH2. some examples of homologous series are alkanes, alkenes, alcohols, carboxylic acids.
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How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
Ionization energy is
mamaluj [8]

Explanation:

the quantity of energy that an isolated, gaseous atom in the ground electronic state must absorb to discharge an electron, resulting in a cation.

7 0
3 years ago
Convert 7.34 miles into meters (1mile = 1.6 Km)
Lera25 [3.4K]

Answer:

11812.58 meters = 11.81258 Km

Explanation:

hope that helps

8 0
3 years ago
What is the charge of a carbon ion that has gained 4 electrons?
olya-2409 [2.1K]

Answer:

Negative

Explanation:

Any atom gaining electrons will get a negative change since the charge of the electron is negative.

6 0
3 years ago
What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0
3 years ago
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