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marta [7]
3 years ago
14

Explain and describe how the photoelectric effect occurs on an atomic level in terms of protons, neutrons, and electrons

Chemistry
1 answer:
Aloiza [94]3 years ago
4 0

ANSWER:

Explaining the experiments on the photoelectric effect. How these experiments led to the idea if light behaving as a particle of energy called a photon.

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The value of Kc for the reaction between water vapor and dichlorine monoxide, H2O(g) 1 Cl2O(g) 4 2 HOCl(g) is 0.0900 at 25°C. De
max2010maxim [7]

Answer:

[HOCl] = 0.001 127 mol·L⁻¹; [H₂O] = [Cl₂O] = 0.003 76 mol·L⁻¹

Explanation:

The balanced equation is

H₂O + Cl₂O ⇌ 2HOCl

Data:

     Kc = 0.0900

[H₂O] = 0.004 32 mol·L⁻¹

[Cl₂O] = 0.004 32 mol

1. Set up an ICE table.

\begin{array}{ccccccc}\rm \text{H$_{2}$O}& + & \text{Cl$_{2}$O} & \, \rightleftharpoons \, & \text{2HOCl} & & \\0.00432 & & 0.00432 & & 0 & & \\-x &&-x&&+2x&&\\0.00432-x &&0.00432 - x& & 2x&&\\\end{array}

2. Calculate the equilibrium concentrations

K_{\text{c}} = \dfrac{\text{[HOCl]$^{2}$}}{\text{[H$_{2}$O][Cl$_2$O]}} = \dfrac{(2x)^{2}}{(0.00432 - x)^{2}} = 0.0900\\\\\begin{array}{rcl}\dfrac{4x^{2}}{(0.00432 - x)^{2}} &=& 0.0900\\ \dfrac{2x }{0.00432 - x} & = & 0.300\\2x & = & 0.300(0.00432 - x)\\2x & = & 0.001296 - 0.300x\\2.300x & = & 0.001296\\x & = & \mathbf{5.63\times 10^{-4}}\\\end{array}

[HOCl] = 2x mol·L⁻¹ = 2 × 5.63 × 10⁻⁴ mol·L⁻¹ =0.001 127 mol·L⁻¹

[H₂O] = [Cl₂O] = (0.004 32 - 0.000 563) mol·L⁻¹ = 0.003 76 mol·L⁻¹

Check:

\begin{array}{rcl}\dfrac{0.001127^{2}}{0.00376^{2}} & = & 0.0900\\\\\dfrac{1.270 \times 10^{-6}}{1.411 \times 10^{-5}} & = & 0.0900\\0.0900 & = & 0.0900\\\end{array}

OK.

7 0
3 years ago
A scientist observed a 5-mL sample of an unknown substance. It is a blue liquid with a density of 1.2 g/cm. the substance reacts
LenaWriter [7]
Characteristic properties can be used to describe and identify the substances, while non-characteristic properties, although can be used to describe the substances, cannot be used to identify them.

Temperature, mass, color, shape and volume are examples of non-characteristic properties.

Density, boiling point, melting point, chemical reactivity are examples of characteristic properties.

List of the properties observed by the scientist:
-----------------------------------------------------------------
Property                                     Type of property
----------------------------------------------------------------
Volume: 5 ml                              non-characteristic
----------------------------------------------------------------
Color: blue                                 non-characteristic
----------------------------------------------------------------
State: liquid                                characteristic
------------------------------------------------------------
density: 1.2 g/cm                        characteristic
------------------------------------------------------------
Reaction: reacts with CO2         characteristic
----------------------------------------------------------
5 0
3 years ago
Write skeleton equations for the following reactions
mojhsa [17]
Al +3CuCl--->AlCl3+3Cu , its balanced equation
8 0
3 years ago
What is the value of the van't Hoff factor for KCl if a 1.00m aqueous solution shows a vapor pressure depression of 0.734 mmHg a
yaroslaw [1]

<u>Answer:</u> The Van't Hoff factor for KCl is 1.74

<u>Explanation:</u>

We are given:

Molality of solution = 1 m

This means that 1 mole of a solute is present in 1 kg of solvent (water) or 1000 grams of water

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of water = 1000 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

\text{Moles of water}=\frac{1000g}{18g/mol}=55.56mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of solute = 1 moles

Total moles = [1 + 55.56] = 56.56 moles

Putting values in above equation, we get:

\chi_{(solute)}=\frac{1}{56.56}=0.0177

The equation used to calculate relative lowering of vapor pressure follows:

\frac{p^o-p_s}{p^o}=i\times \chi_{solute}

where,

\frac{p^o-p_s}{p^o} = relative lowering in vapor pressure = 0.734 mmHg

i = Van't Hoff factor = ?

\chi_{solute} = mole fraction of solute = 0.0177

p^o = vapor pressure of pure water = 23.76 torr

Putting values in above equation, we get:

\frac{0.734}{23.76}=i\times 0.0177\\\\i=1.74

Hence, the Van't Hoff factor for KCl is 1.74

7 0
3 years ago
What is the symbol for an atom containing 20 protons and 22 neutrons?
olya-2409 [2.1K]
It is an isotope of Calcium, which has the symbol Ca
6 0
3 years ago
Read 2 more answers
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