A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride
<span>c. About one month
To answer this question, TAKE A LOOK AT THE GRAPH. If you do so, you'll see that the first peak for prey happens at about 2.5 months. The first peak for predators happens at about 3.5 months, or in other words, lags by about a month. Looking at the second peak for prey and predator you see the figures of 8 months and 9 months. Another lag of about 1 month. Looking at the third peak, you see a bit past 13 months and a bit past 14 months. Another one month lag. Therefore the answer is "c. About one month"</span>
Answer:
1. The dye that absorbs at 530 nm
Explanation:
With a larger HOMO-LUMO gap, there's also a higher absorption energy, so this means that the dye with the higher absortion energy has the larger HOMO-LUMO gap.
The relationship between energy and wavelenght can be expressed by the formula E = hc/λ, this means that the <em>lower</em> the wavelenght, the <em>higher</em> the energy is. So the dye that absorbs at a lower wavelenght has a larger HOMO-LUMO gap.
Answer:
I
Explanation:
The complete question can be seen in the image attached.
We need to understand what is actually going on here. In the first step that yields product A, the sodamide in liquid ammonia attacks the alkyne and abstracts the acidic hydrogen of the alkyne. The second step is a nucleophilic attack of the C6H5C≡C^- on the alkyl halide to yield product B (C6H5C≡C-CH3CH2).
Partial reduction of B using the Lindlar catalyst leads to syn addition of hydrogen to yield structure I as the product C.
