The answer is nonproportional.
A triangular prism Vol. = area (A) of the triangular base × height (h) of prism
A triangular pyramid V = A × 1/3 h
So since they have same base A and h, the V of the pyramid will be exactly 1/3 the V of the prism
Answer:
Sam gets £30 and Bethan gets £24.
Why?
When dealing with ratios, add up the numbers in the ratio.
5 + 4 = 9
Now, divide the total amount of money by that number.
£54/9 = 6
Now you have the base rate. Multiply each quantity in the ratio by this number.
5*6 = 30
4*6 = 24
Now, the ratio is (in euro) 30:24. This means that Sam has £30 and Bethan has £24.
Check:
30 + 24 = 54
You move the decimal point forward until it reaches the one so it looks like this:
1.4 x 10⁵
the exponent, 5, just tells you how many spaces the decimal point moved.
6. Take your compass and place the pointed edge on point B. Place one point on each side of B, each the same distance away from B. Next, place your compass on one of the two new points and extend your compass to draw a circle. Repeat with the SAME radian from the other point. Find where the two circles intersect with each other and draw a line from the points of intersection to point B. Place point A anywhere on that line that you just created and then you're done!
7. Select any place along either line and place point S on it. Next, using the same method as above, draw two circles with the same radius around both points S and R. Draw a line through the intersection points. Locate the intersection where your new line connects with the line across from the shared line of RS. Place a point at the intersection, for your reference, then connect that point to point S. Now you have completed this problem as well.
8. Use a straight edge to draw one line. Place points A and B on each end. Use the circle method yet again to find a line perpendicular to line AB. Next, take your compass and set it to the distance from point A to B. Use that same distance to make a point on the perpendicular line. This creates point C. The final step is to connect A with C and B with C.
