A) (x, y) → (3x, 3y)
<h2>
Explanation:</h2>
When you dilate an object, you enlarge or reduce the size of it. To do this, we need a scale factor which allows us to make the object larger or smaller depending on the value of that factor. Let's call this factor as k, then it is true that:
- If k > 1, the object will be larger than the original one.
- If k < 1, the object will be smaller than the original one.
If the dilation is performed centered at the origin, then corresponding points of the original and dilated figures will be connected by straight lines, being the center of dilation the point where all the lines meet.
The only option that meets this requirement is:
A) (x, y) → (3x, 3y)
Whose scale factor is k = 3 making the dilated figure larger than the original one.
<h2>Learn more:</h2>
Dilation: brainly.com/question/10946046
#LearnWithBrainly
Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90
has a pvalue of 0.9649
X = 82
has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
2016
Step-by-step explanation:
To solve this problem, let us find the prime factors of the given numbers:
96
8 x 12
2 x 2 x 2 2 x 2 x 3
2⁵ x 3
144
12 x 12
2 x 2 x 3 2 x 2 x 3
2⁴ x 3²
126
2 x 63
2 7 x 9
2 3 x 3 x 7
2 x 3² x 7
So, the lowest common multiple = 2⁵ x 3² x 7 = 2016
