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3 years ago

A sum of compounded annually, amount to Rs

Mathematics

1 answer:

wolverine [178]3 years ago

8 0

Answer:

Step-by-step explanation:

ollowing is the formula for calculating compound interest when time period is specified in years and interest rate in % per annum.

A = P(1+r/n)nt

CI = A-P

Where,

CI = Compounded interest

A = Final amount

P = Principal

t = Time period in years

n = Number of compounding periods per year

r = Interest rate

Calculation Examples

You can solve for any variable by rearranging the compound interest formula as illustrated in the following examples:-

1. What is the compound interest of 75000 at 7.9% per annum compounded semi-annually in 3 years?

Ans. A = P(1+r/n)nt = 75000(1 + (7.9 / 100) / 2)6 = 94625.51

Interest = 94625.51 - 75000 = 19625.51

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You can solve the following proportion by cross multiplying. What will the equation be after you cross multiply? 3/9 = x/15

aksik [14]

3 x
---- = -----
9 15

so 9x = 45 (and x =5).

4 0

3 years ago

Read 2 more answers

Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.

Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number $2.14$ and a fraction $\frac{5}{20}$

Now, according to the Commutative property of Addition:

For any two numbers $a$ and $b$ :

$a+b = b+a$

So, for $2.14$ and $\frac{5}{20}$

Let us add

$2.14+\frac{5}{20} = \frac{214}{100} +\frac{5}{20}$

$=\frac{214}{100} + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100} + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39$

Also,

$\frac{5}{20} + 2.14 = \frac{5}{20} + \frac{214}{100}$

$= \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100} + \frac{214}{100} \\ \\= 0.25 + 2.14 \\ \\ = 2.39$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Commutative Property of Addition is satisfied.

For Associated Property of Addition

Let us take two same decimal numbers $2.14$ , $7.25$ and a fraction $\frac{5}{20}$

Now, according to the Associated property of Addition:

For any three numbers $a$ , $b$ and $c$

$a + (b+c) =(a+b) + c$

So, for $2.14$ , $7.25$ and $\frac{5}{20}$

The Left hand side:

$a + (b+c)$

$2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})$

$= 2.14 + (\frac{725}{100} + \frac{25 }{100})$

$= 2.14 + (\frac{750}{100} )$

$= \frac{214}{100} + \frac{750}{100}$

$= \frac{964}{100}$

$=9.64$

The Right hand side:

$(a + b )+c$

$(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}$

$= 9.39 + \frac{5 \times 5 }{20 \times 5}$

$= 9.39 + \frac{25}{100}$

$= 9.39 + 0.25$

$= 9.64$

Thus,

$(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Associative Property of Addition is satisfied.

8 0

3 years ago

A soccer ball has an interior diameter of 22 cm. How many cubic centimeters of air does a soccer ball

Delvig [45]

Answer:

Volume of soccer ball = 5,572.45 Cm³ (Approx)

Step-by-step explanation:

Given:

Diameter of soccer ball = 22 Cm

Radius of soccer ball = 22 Cm / 2 = 11 Cm

Find:

Volume of soccer ball = ?

Computation:

$Volume\ of\ soccer\ ball = \frac{4}{3} \pi r^3\\\\ Volume\ of\ soccer\ ball = \frac{4}{3} \times\frac{22}{7} \times 11^3\\\\ Volume\ of\ soccer\ ball = 5,572.45332$

Volume of soccer ball = 5,572.45 Cm³ (Approx)

Therefore, Soccer ball contain 5,572.5 Cm³ of air.

5 0

4 years ago

Jennifer is saving money to buy a bike. The bike costs $245. She has $125 saved, and each week she adds $15 to her savings. How

Lady bird [3.3K]

It will take her 8 weeks to have enough money for a bike. I made the equation 125+15x=245 and multiplied 15 by 8 to get exactly 245

8 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.

IrinaVladis [17]

Answer: C= (3,2) and D=(2.2, 2.8)

Step-by-step explanation:

The coordinates of point P(x,y) divides a line segment having end points M ${x_1,y_1}$ and N $(x_2,y_2)$ in m:n will be :-

$x=\dfrac{mx_2+nx_1}{m+n}\ ;\ y=\dfrac{my_2+ny_1}{m+n}$

Given : The endpoints of AB are A(1,4) and B(6,-1).

If point C divides AB in the ratio 2 : 3, the coordinates of point C will be :-

$x=\dfrac{2(6)+3(1)}{2+3}\ ;\ y=\dfrac{2(-1)+3(4)}{2+3}$

Simplify,

$\\\\\Rightarrow x=3\ y=2$

Thus , coordinate of C= (3,2)

If point D divides AC in the ratio 3 : 2, the coordinates of point D will be :-

$x=\dfrac{3(3)+2(1)}{3+2}\ ;\ y=\dfrac{3(2)+2(4)}{3+2}$

Simplify,

$\\\\\Rightarrow x=3\ y=2$

Thus , coordinate of D= (2.2,2.8)

4 0

4 years ago

Read 2 more answers