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Naya [18.7K]
3 years ago
8

I need help! Will this would be very appreciated!pls

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

Answer:

No real

solution

Step-by-step explanation:

Firstly, let us check if we would be having a real solution

We start by rewriting the equation

We have this as;

8x^2 -25x + 24 = 0

We proceed to get the discriminant

Mathematically, we have this as;

D = b^2 - 4ac

b is the coefficient of x which is -25

a is the coefficient of x^2 which is 8

c is the last number which is 24

So we have;

D = (-25)^2 - 4(8)(24)

D = 625 - 768 = -143

Since the value of the discriminant is negative, there cannot be real roots

What we have as solution are complex roots

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Solution

(a) setting f(x) = 0

\begin{gathered} 3x^4-18x^3-21x^2+144x-108=0 \\  \\ (x+3)(x-1)(x-2)(x-6)=0 \\  \\ \Rightarrow x=-3,1,2,6 \end{gathered}

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Maximum = (1.5, 15.188)

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\begin{gathered} (-1.7,\frac{3}{2}),(4.7,\infty) \\  \end{gathered}

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(-\infty,-1.7),(\frac{3}{2},4.7)

g)

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