Answer:

Step-by-step explanation:
Given:
The above triangle
Required
Solve for AB in terms of a, b and angle C
Considering right angled triangle BOC where O is the point between b-x and x
From BOC, we have that:

Make h the subject:

Also, in BOC (Using Pythagoras)

Make
the subject

Substitute
for h
becomes


Factorize

In trigonometry:

So, we have that:

Take square roots of both sides

In triangle BOA, applying Pythagoras theorem, we have that:

Open bracket

Substitute
and
in 


Open Bracket

Reorder

Factorize:

In trigonometry:

So, we have that:


Take square roots of both sides

One possible divided is the number 1236.
If 5 went into 1235 the quotient would be exactly 247. However, there needs to be a remainder. So let's just change the number to 1236. Then, there will be a remainder of 1.
The simplest ratio is 1/3. Equivalent ratios would be 3/9 and 5/15.
Depends greatly on the type of function.
Some things to keep in mind:
1.) the value of the denominator of a fraction cannot be zero
2.) the inside of an even root cannot be less than zero
3. The argument of a logarithmic function must be greater than zero
4. Plus many more other rules and such
But a simpler explanation, just find out what values x can be for the given function, and what y can be.
The x values make up the domain, the y, the range
Graphs are helpful
Hope this helps!