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Kaylis [27]
2 years ago
6

Help ….

Chemistry
1 answer:
VikaD [51]2 years ago
7 0

Answer: 3 and 4 are the answers.

Explanation: i took the quiz.

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Which organism is a tertiary consumer?<br> clownfish<br> brittle star<br> killer whale<br> octopus
vlada-n [284]

Answer:

killer whale

Explanation:

7 0
3 years ago
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8. A sample of chloroform is found to contain 24.0 g of carbon,212.8 g of chlorine, and 2.02 g of hydrogen. If a second sample o
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Answer:

595.5

Explanation:

chloroform with 24.0 g C was 238.2 g

24g/238.2g= 60g/x

595.5

4 0
3 years ago
Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He
marysya [2.9K]

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140

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3 years ago
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Bromine has a density of 3.10g/cm3. If you have 50.0 ML of bromine, how many grams do you have?
Zanzabum

Answer:

The answer is

<h2>155 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of bromine = 50 mL

density = 3.10 g/cm³

It's mass is

mass = 50 × 3.10

We have the final answer as

<h3>155 g</h3>

Hope this<u> </u>helps you

5 0
3 years ago
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The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
Hitman42 [59]

<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

7 0
3 years ago
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