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Brut [27]
2 years ago
7

PLS HELP: A box is 9 inches wide, 3 inches long, and 12 inches high. It is completely filled with blocks that are each 1 cubie i

nch in volume. If 20 blocks were taken out of the box, how many blocks would remain in the box?

Mathematics
1 answer:
LekaFEV [45]2 years ago
3 0

Answer: 304

Step-by-step explanation: first you multiply 9, 3, and 12 which equals 324. Then you subtract 20 from 324 and you get 304.

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HELPPPPPPPPP 55 POINTS Isabel graphed the following system of equations.
Arturiano [62]

Answer:

1.  Substitute y = -3x +4 for y in the first equation

2.  Combine like terms and isolate x

3.  Substitute in x into the 2nd equation to get y

Step-by-step explanation:

1.  Substitute y = -3x +4 for y in the first equation

2x- (-3x+4) = 6

2.  Combine like terms

5x -4 = 6

5x -4 +4 = 6+4

5x=10  Divide by 5 to isolate x

5x/5 =10/5

x=2

3. Substitute in x into the 2nd equation to get y

y = -3x +4

y = -3(2) +4

y = -6+4

y=-2

(2,-2)

5 0
3 years ago
12. In a certain cafe, all the sandwiches and drinks are priced the
kakasveta [241]

The cost of one sandwich is $3.90

The cost of one deknk is $1.50

hopefully this is correct

7 0
2 years ago
Compute the sales tax on the following transactions. An article retails for $37.50. The city sales tax is 6%, and the federal ex
ratelena [41]
First you must find the rate of both taxes. Since its 8% and 6%, you must add them both together, then divide them by 100. 

14/100 = .14

Then for both rates you must add 1 because it is a tax increase.

1 + .14 = 1.14

Finally times 37.50 with 1.14

37.50(1.14) = <span>42.75
</span>
<span>$42.75 is the answer.</span>

 
7 0
3 years ago
Read 2 more answers
Free points insta: (jqyneii) giving Brainliest to the first person :D make sure to get outside its good for you ily &lt;3
kiruha [24]

Answer:

THANKS FOR THE POINTS

Step-by-step explanation:

3 0
2 years ago
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
2 years ago
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