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andriy [413]
3 years ago
7

Work out the value of (1.7X10^4) X (8.5X10^-2) in standard form

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Answer:

1.445 × 10³ hope it helped goodluck!

kvv77 [185]3 years ago
5 0
answer is 1.445 x 10^3
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Find S15 for the geometric series 72 + 12 + 2 + 1/3 +…
Gemiola [76]
S1 = 72
S2 = 12 = 72*(1/6)
S3 = 2 = 72*(1/6)^2
.
.
.
S15 = 72*(1/6)^14 = 9.18*10^(-10)
5 0
3 years ago
Find the measure of angle K.
BabaBlast [244]
Every triangle have three angles that add up to 180°. With this information, we can find out the missing angle.

The sum of three angles should add up to 180°. 

148° + 11° + K = 180°

Where k is the missing angle.

Solve for K.

Combine like terms.

148° + 11° + K = 180°
159° + K = 180°

Subtract both sides by 159°.

159° + K = 180°
159° - 159° + K = 180° - 159°
K = 21°

So, the missing length is 21°.
7 0
3 years ago
Sweets are sold loose, or pre-packed in 120g bags. The 120g bags are ?1.49 each. The loose sweets are ?0.89 for 100g. By calcula
tester [92]

Answer:

The loose sweets at ?0.89 for 100 g.


Step-by-step explanation:

First, calculate the price per gram. You do this by dividing the price by the grams.

?1.49 / 120 g =  1.49 / 120 = 0.0124 (4 dp)

Because the answer was very long, I have rounded it to 4 decimal places (4 dp).

?0.89 / 100 g = 0.89 / 100 = 0.0089

Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.

0.0124 x 100 = 1.24

0.0089 x 100 = 0.89

Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.






6 0
3 years ago
What is the intersection of plane STXW and plane TUYX?
posledela

Answer:

point t

Step-by-step explanation:

6 0
3 years ago
The line with equation x + y = 0 coincides with the terminal side of an angle θ in standard position in Quadrant II .
Naya [18.7K]

Answer:

tanθ = -1

m=tanθ = -1

Step-by-step explanation:

Step 1:-

using formula m=tanθ

Given straight line is x+y=0

The given straight line is passing through the origin so y = -x

straight line is passing through the origin so y = m x

m = -1

Step3:-

The line with equation x+y=0 with the terminal side of an angle θ in standard position in Quadrant II i.e., θ = 90+45=135

 m  = tanθ

 m  = tan(90+45)

  m   = - cot 45

   m   = -1

Step4:-  m =tanθ =-1

8 0
3 years ago
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