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Roman55 [17]
3 years ago
5

What's the answer to n+4.5-0.3n-3

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
1. Collect like terms

(n - 0.3n) + (4.5 - 3)

2. Simplify

0.7n + 1.5

Final Answer:

0.7n + 1.5
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Will someone please help me here
frez [133]

Hey!

You have to divide the total amount she has by the surface area.

Surface area = 2(wl+hl+hw)

That gives you:

(15 + 18 + 30) \times 2 \\ 63 \times 2 = 126

The surface area is 126 ft. Now divide the total amount she has by the surface area.

1,134 \div 126 = 9

<em>That means she can cover 9 boxes</em>

\framebox{She can cover 9 boxes}

8 0
3 years ago
Find the least number by which 1470 must be divided to get a number which is the perfect square?
Nutka1998 [239]
1470|2\\.735|5\\.147|3\\.\ 49|7\\.\ \ \ 7|7\\.\ \ 1|\\\\1470=2\times5\times3\times7^2=30\times49\\\\Solution:this\ a\ number\ equal\ 30,\ because\ 1470:30=49=7^2
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1. the sum of two rational numbers is always always a (irrational number / rational number)
Blizzard [7]

One

The sum of two rational numbers is always rational. sqrt(9) + sqrt(25) = 3 + 5 which is rational. sqrt(16/100) = 4/10 = 2/5 is also rational. 3/28 is rational as well.

Two

Those are irrational. sqrt(10) + pi = ???? You cannot reduce this to any kind of fraction. Two irrationals always give a rational.

Three

The irrational number controls the answer. 10 + sqrt(5) is irrational. The 10 is OK. It is raional, but sqrt(5) is not a rational number.

8 0
3 years ago
[12÷(9-6)]+4×6 <br>please help ​
Pavel [41]

The answer is 28 ez.

8 0
3 years ago
Read 2 more answers
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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