Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure

3 0

3 years ago

Read 2 more answers

I need help on 11-16

alisha [4.7K]

I cant see all of 11 and 14
12:
$3f = 18 \\ \frac{3f}{3} = \frac{18}{3} \\ f = 6$
13:
$3f = {3}^{2} \\ 3f = 9 \\ \frac{3f}{3} = \frac{9}{3} \\ f = 3$
15:
$3h = 9 + 10 \\ 3h = 19 \\ \frac{3h}{3} = \frac{19}{3} \\ h = 6.3$
16:
$3f = 27 - 21 \\ 3f = 6 \\ \frac{3f}{3} = \frac{6}{3} \\ f = 2$

6 0

3 years ago

A spherical balloon is inflated with gas at a rate of 600 cubic centimeters per minute.

Semmy [17]

C. The rate of change of the radius is a cubic relationship

6 0

3 years ago

Please help. y = t^2 cos tx = t sin tDetermine dy/dx​

Please help. y = t^2 cos tx = t sin tDetermine dy/dx