(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
Answer:
116
Step-by-step explanation:
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![[n][n+8]=0](https://tex.z-dn.net/?f=%5Bn%5D%5Bn%2B8%5D%3D0)
if either or both of
![[n]](https://tex.z-dn.net/?f=%5Bn%5D)
and
![[n+8]](https://tex.z-dn.net/?f=%5Bn%2B8%5D)
are 0, i.e. if one or both of
and
are even. But both will be even if
is even, and odd otherwise, so any even
will be a solution, e.g.
.
Answer:
Step-by-step explanation:
1/25
