What is the solution to the above system of equations?
2 answers:
(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
= - 1
solution is (7 , -1)
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Correct Answer:
Second option
Solution:
The given sequence is:
2.2, 6.6, 11, ...
If we observe the sequence it is an Arithmetic Sequence as the difference between two consecutive terms is the same.
6.6 - 2.2 = 4.4
11 - 6.6 = 4.4
First we find the general term for this sequence.
first term = 2.2
d = 4.4
So,
This general term will be placed inside the summation sign with limits from 1 to 5 to give the sum of first 5 terms of the given sequence. So the correct answer is Second Option
Second option
Solution:
The given sequence is:
2.2, 6.6, 11, ...
If we observe the sequence it is an Arithmetic Sequence as the difference between two consecutive terms is the same.
6.6 - 2.2 = 4.4
11 - 6.6 = 4.4
First we find the general term for this sequence.
d = 4.4
So,
This general term will be placed inside the summation sign with limits from 1 to 5 to give the sum of first 5 terms of the given sequence. So the correct answer is Second Option
Answer:
17) x=8
18) or
Step-by-step explanation:
So the rule is , "c" being the hypothenuse, or the long line that is opposite to the right angle.
17) We know that both values of x are equal to each other, which makes everything 10x easier!
(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)
<em>simplify</em> (╥︣﹏╥)
x=8
18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)
Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!
It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!
The more you do these, the easier they'll get, so don't worry!