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Veronika [31]
3 years ago
12

The official all-time high temperature in Osoyoos, B.C., was 43°C in July 1998. The official all-time low temperature was –21°C

in February 1996. What is the difference between the two temperatures? Please show all your work.
Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer: 64°C

Step-by-step explanation:

Official all-time high temperature = 43°C

Official all-time low temperature = –21°C

The difference between the two temperatures will be calculated by subtracting the low temperature from the high temperature. This will be:

= 43°C - (-21°C)

= 43°C + 21°C

= 64°C

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Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.
alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

6 0
3 years ago
Whats the correct answer??
Tpy6a [65]

use the midpoint formula. It's x1 + x2 / 2, y1+y2/2. When you solve you get (0, 1/2) is the midpoint. Hope this helps


8 0
3 years ago
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