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3 years ago

What is the answer please??

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

6 0

I mean, I would assume it’d just be n/2? Because you have n, which you don’t know the number for, and then you divide by 2, leaving n divided by 2 which is n/2

xenn [34]3 years ago

5 0

Answer:

Answer is n/2

Step-by-step explanation:

I started with the constant n

In second step I divided the n by 2

$answer \: is \: \: \frac{n}{2}$

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What is the price if it’s 20% off $30

Xelga [282]

Answer: $24

Step-by-step explanation:

5 0

3 years ago

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A bag contains 25 balls 20 of which are blue what percentage of balls are not blue

Artist 52 [7]

Answer:

20%

Step-by-step explanation:

20/25 = blue

This means 5/25 of the balls in the bag are NOT blue

(25-20 = 5)

We need to convert 5/25 to a percentage

$\dfrac{5}{25} = \dfrac{5\times4}{25\times4}=\dfrac{20}{100}$

% = per cent

"per" means "out of"

"cent" means "one hundred"

20/100 = 20%

7 0

1 year ago

Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?

9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

$f(x)=\frac{(x-1)(x^2-4)}{x^2-a}$

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that $x=\sqrt{a}$ will annulate the denominator, i.e

$(\sqrt{a})^2-a = a-a = 0$ . But, if a = 1 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}$

so, the value $x=\sqrt{a} = \sqrt{1} = 1$ won't annulate the denominator.

Now, for a = 4 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1$

so, the value $x=\sqrt{a} = \sqrt{4} = 2$ won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0

3 years ago

What number must you add to complete the square? x2 + 12x = -5

VARVARA [1.3K]

You must add 6 to complete the square.
x^2+12x+(6)=-5(6)

7 0

3 years ago

What would i use to factor 15x^2+10x-9x-6

boyakko [2]

I would recommend combing like terms (ex- 10x-9x=x) so it could be 15x^2+x-6 . I recommend using something like mathpapa to show you step-by-step how to do it, and if you know, then it just gives you a quick answer

3 0

3 years ago