For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1
So we first need to find the slope of the reference line.
m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4
So the perpendicular line will have a slope of:
5m/4=-1
m=-4/5
So our perpendicular line so far is:
y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"
-1=-4(3)/5+b
-1=-12/5+b
-5/5+12/5=b
7/5=b
So the line is:
y=-4x/5+7/5 or more neatly
y=(-4x+7)/5
y=-0.8x+1.4
Answer:
Step-by-step explanation:
Let
x-------> the length side of the rectangle
y------> the width side of the rectangle
we know that
---> equation A
---> equation B (given problem)
substitute equation B in equation A
so
the coordinate of the top-left vertex of the rectangle is equal to
Answer:
C) (square root 2)/2
Step-by-step explanation:
In quadrant III, the sine of an angle is positive. The value will be ...
sin(Θ) = √(1 -cos(x)^2) = √(1 -(-√2/2)^2) = √(2/4)
sin(Θ) = (√2)/2
Answer:
-350% -0.4% -40% -37.5% hope this helps!
Step-by-step explanation:
Answer:
m MN = 70°
Step-by-step explanation:
∠MLN is an angle formed by the chords ML and LN and is calculated as
∠MLN = 0.5( m arc MN ), that is
35° = 0.5 arc MN ( multiply both sides by 2 )
arc MN = 2 × 35° = 70°
