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Lunna [17]
3 years ago
11

If the statement "If I am hungry, then I am not happy" is assumed to be true, is its negation, "If I am not hungry, then I must

be happy," also always true?
Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0
Its negation is not always true. You can be unhappy while not being hungry!
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a rectangle has a width that is 7 centimeters less than its length, and its area is 330 square centimeters. What are the dimensi
Serggg [28]
Length = 22 cm
width = 22 cm - 7 cm = 15 cm
8 0
3 years ago
Read 2 more answers
solve the following inequality. Then plays the correct answer in the box provided. answer in terms of a mixed number. 2(P+1)+3(P
Vesnalui [34]
2(P+1)+3(P+2)>2
Distribute
2P+2+3P+6>2
Simplify
5P+8>2
Subtract 8 from both sides
5P>-6
Divide both sides by five
P>(-6/5)
Turn to mixed number and you're done.
P>-1 and 1/5
5 0
4 years ago
On the written portion of her driving test, Sara answered 84% of the questions correctly. If Sara answered 42 questions correctl
kotykmax [81]
There is 50 questions hole this helps
7 0
3 years ago
Sean read 1515 of a book in 112112 hours. How long will it take Sean to read 1212 of this book?
levacccp [35]
I guess your question is
<span>Sean read 15 of a book in 112 hours. How long will it take Sean to read 12 of this book?

15 books ........112 hours
12 books..........? hours

12 x 112 / 15 = 89.6 hours.

</span>
4 0
3 years ago
Identify the best big-O estimate for the number of comparisons used by the algorithm that determines the number of 1s in a bit s
Westkost [7]

Answer:

0(n)

Step-by-step explanation:

Result previous exercise:  

procedure count(a1a2...an : string with n > 1)

i:=0

for k:=1 to n

if ak =1 then i:=i + I

return i  

<em>Note</em><em>: If you use a different algorithm, then you could possible get different results.  </em>

<u>SOLUTION  </u>

There is only one part of the code that contains an operation (comparison), namely if a_k =1  

This comparison is executed in every iteration of the for-loop  

k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.  

Thus in total there are then n comparisons, while n is 0(n).

5 0
3 years ago
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