The value of x is 67°
<u>Step-by-step explanation:</u>
Given that
PN=LN
NP||MQ
QL bisects <PQM
therefore <PQL=<LQM
NP||MQ and NM is a transversal
<PNL+<LMQ=180°(angles on the same side of the transversal are supplementary)
<PNL+54=180°
<PNL=180-54=126°
Consider ΔPNL
since PN=NL,the triangle is isocelus
<NPL=<NLP=a
<NPL+<NLP+<PNL=180°
a+a+126=180°
2a+126=180
2a=180-126
=54°
a=54/2=27°
consider the point L
<NLP+<PLQ+<MLQ=180°
27+70+<MLQ=180
<MLQ=180-97=83°
consider ΔLQM
<LQM+<LMQ+LMQ=180
<LQM+83+54=180
<LQM=180-(83+54)=180-137=43°
<PQL=43°(since<PQL=<LQM)
considerΔPQL
x+70+<PQL=180°
x+70+43=180°
x+113=180
x=180-113
=67°
The value of x is 67°
Step-by-step explanation:
Step-by-step explanation: Given the expression sin(11pi/2 +x) =-1/2. Take the arcsin of both sides. sin⁻¹[sin(11pi/2 +x)]
Answer:
16008
Step-by-step explanation:
Sum of an arithmetic sequence is:
S = (n/2) (2a₁ + (n−1) d)
or
S = (n/2) (a₁ + a)
To use either equation, we need to find the number of terms n. We know the common difference d is 1 − (-9) = 10. Using the definition of the nth term of an arithmetic sequence:
a = a₁ + (n−1) d
561 = -9 + (n−1) (10)
570 = 10n − 10
580 = 10n
n = 58
Using the first equation to find the sum:
S = (n/2) (2a₁ + (n−1) d)
S = (58/2) (2(-9) + (58−1) 10)
S = 29 (-18 + 570)
S = 16008
Using the second equation to find the sum:
S = (n/2) (a₁ + a)
S = (58/2) (-9 + 561)
S = 16008
Answer:
1,670
Step-by-step explanation:
35x8= 280
1950-280= 1,670
