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Simora [160]
3 years ago
14

I really need help again.

Mathematics
1 answer:
REY [17]3 years ago
8 0

Answer:

Y =  -1/2X +4

Step-by-step explanation:

x1 y1  x2 y2

2 3  0 4

   

(Y2-Y1) (4)-(3)=   1  ΔY 1

(X2-X1) (0)-(2)=    -2  ΔX -2

   

slope= -  1/2    

B= 4          

   

Y =-0.5X +4    

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Given segment AB with points (-4, 8) and (6, 3) respectively. Find the coordinates of point P that partitions Segment AB in the
netineya [11]

Answer:

P = (2,5)

Step-by-step explanation:

Given

A(-4,8)

B(6,3)

m:n = 3 : 2

Required

Determine P

Since P divides the segment into 3:2, P is calculated using

P = (\frac{nx_1 +m x_2}{m+n},\frac{ny_1 + my_2}{m+n})

Where

(x_1,y_1) = (-4,8)

(x_2,y_2) = (6,3)

m:n = 3 : 2

Substitute these values in the above formula:

P = (\frac{2 * -4 +3 * 6}{3 + 2},\frac{2 * 8 + 3 * 3}{3 + 2})

P = (\frac{-8 +18}{3 + 2},\frac{16 + 9}{3 + 2})

P = (\frac{10}{5},\frac{25}{5})

P = (2,5)

8 0
3 years ago
The graph for the equation y = 2 x minus 2 is shown below. On a coordinate plane, a line goes through points (0, negative 2) and
weqwewe [10]

Answer:

i think it is b correct me if i am rong

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which is bigger? 36.2 or 36.12<br>which is bigger? 9.18 or 9.19<br>which is bigger? 7.6 or 7.60​
galben [10]

Answer:

36.20

9.19

7.6 and 7.60 are the same number

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A uniform border on a framed photograph has the same area as the photograph. What are the outside dimensions of the border if th
Black_prince [1.1K]

Given dimension of photograph = 25cm * 20cm

So area of photograph = 500cm²

Now, let the width of frame border be = x

So, dimensions of photograph + frame= (25 + 2x)*(20 + 2x)

As given, the area of frame is same as photograph , so

Area of picture + frame = 1000cm  ²

Hence, area equals

4x^{2}+90x+500=1000

4x^{2}+90x-500=0

2x^{2}+45x-250=0

Solving this quadratic equation,

For the quadratic equation of the form ax^{2}+bx+c=0 , solution is:

x1,2 = \frac{-b+\sqrt{b^{2}-4ac}}{2a}

Now putting a=2, b=45, c= -250 and solving he above equation, we get two values of x.

x = -27.11 (discard it as it is negative)   and

x = 4.61 cm

Hence the dimensions of the frame are:

20+2x = 20+2(4.61) = 29.22 cm

25+2x = 25+2(4.61) = 34.22 cm



7 0
3 years ago
The knife shown below is 14 inches long. write an algebraic expression that represents the length of the blade (in inches).
jekas [21]
Let the variable h be handle....and b be the blade
14-h=b    hope this helped
8 0
3 years ago
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